php - 从 MySQL 到 mysqli 的转换不起作用

Question

我正在将现有的 MySQL 转换为 mysqli

但我无法让这段代码正确

mysql_query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");
$new_id = mysql_insert_id();
mysql_query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");

我尝试过的如下所示，但没有奏效

$mysqli->query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");
$new_id = mysqli_insert_id();
$mysqli->query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");

问题在于$new_id = mysqli_insert_id();语句 bcoz 第一个查询正在执行

Answer 1

对于 mysqli 面向对象的样式来获取最后插入的 id 使用这个

$mysqli->insert_id ;

http://www.php.net/manual/en/mysqli.insert-id.php

所以你的查询将是

$mysqli->query("INSERT INTO `sendmsg`(`sendname`, `recievename`, `subject`, `body` , `mdate`, `mtime`) VALUES ('$sendname','$recievename','$subject','$body','$msgdate','$msgtime')");

$new_id = $mysqli->insert_id;

$mysqli->query("INSERT INTO `recievemsg`(`msgid`, `sendname`, `recievename`, `subject`, `body`, `mdate`, `mtime`, `status`) VALUES ($new_id,'$sendname','$recievename','$subject','$body','$msgdate','$msgtime','UNREAD')");