3

我尝试使用 访问我的服务器HttpsURLConnection,得到响应代码 401 - 需要进行身份验证。尝试了以下方法:

            Authenticator.setDefault (new Authenticator() {
                protected PasswordAuthentication getPasswordAuthentication() {
                    return new PasswordAuthentication ("myuser", "!mypassword".toCharArray());
                }
            });

得到响应代码 400 - 错误请求。

基于一些stackoverflow研究,我还尝试使用:

        String authorizationString = "Basic " + Base64.encodeToString(("username" + ":" + "password").getBytes(), Base64.DEFAULT);
        conn.setRequestProperty("Authorization", authorizationString);

同样的问题,代码 400。我也在这篇文章中使用 @Chrispix 方法信任所有主机: Trust Anchor not found for Android SSL Connection 不确定这是否会以某种方式干扰,但这是用于原型并且站点证书不是t 有效,所以我需要绕过检查。

连接是使用这些属性设置的,不确定是否有任何错误或缺失:

        HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
        conn.setReadTimeout(10000 /* milliseconds */);
        conn.setConnectTimeout(15000 /* milliseconds */);
        conn.addRequestProperty("Content-Type", "application/json");
        conn.setRequestMethod("POST");
        conn.setDoInput(true);

谢谢!

4

3 回答 3

1

怎么用HttpClient

HttpClient httpClient= new DefaultHttpClient();
HttpGet httpGet= new HttpGet(yourUrl);
String authString = (yourUserName+":"+yourPassword);
httpGet.addHeader("Authorization", "Basic " + 
    Base64.encodeToString(authString.getBytes(),Base64.DEFAULT));
HttpResponse response = httpClient.execute(httpGet);

似乎您目前想绕过证书检查,此相关链接可能会对您有所帮助

通过 HTTPS 使用 HttpClient 信任所有证书

于 2014-07-09T09:09:07.907 回答
0

试试这个方法

public String sendHttpRequest(String params)
{       
    URL url;
    String result = new String();
    try 
    {
        url = new URL(AUTHENTICATION_SERVER_ADDRESS);
        HttpURLConnection connection;
        connection = (HttpURLConnection) url.openConnection();
        connection.setDoOutput(true);
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Content-Type",
                "application/x-www-form-urlencoded;charset=UTF-8");
        PrintWriter out = new PrintWriter(connection.getOutputStream());

        out.println(params);
        out.close();

        BufferedReader in = new BufferedReader(
                new InputStreamReader(
                        connection.getInputStream()));
        String inputLine;

        while ((inputLine = in.readLine()) != null) {
            result = result.concat(inputLine);  

        }
        in.close();         
    } 
    catch (MalformedURLException e) {
        e.printStackTrace();
    } 
    catch (IOException e) {
        e.printStackTrace();
    }           

    if (result.length() == 0) {
        result = HTTP_REQUEST_FAILED;
    }

    return result;


}

params 参数应该是这种格式

      public String authenticateUser(String username, String password) 
      {
           String params = "username="+ URLEncoder.encode(username,"UTF-8") +
                           "&password="+ URLEncoder.encode(password,"UTF-8") +
                    "&";

          String result = socketOperator.sendHttpRequest(params);       

          return result;
       }

调用此函数进行身份验证...

于 2014-07-09T20:43:26.453 回答
0

似乎我得到了正确的响应——我认为 400 表示请求格式错误,但检查错误流我发现请求很好,但参数错误。菜鸟失误!

于 2014-07-11T23:13:38.503 回答