1

我正在尝试在按下地图时为地图上的每个图标添加一个事件侦听器。我将信息存储在数据库中,我想要检索的值是“i”,但是当我输出“i”时,我得到它的最后一个值,即 5(地图上绘制了 6 个对象)

下面是代码,获取 i 值的最佳方法是什么,而不是对象本身。

var drawLotLoc = function(id) {

    var lotLoc = new GIcon(G_DEFAULT_ICON);             // create icon object
    lotLoc.image = url+"images/markers/lotLocation.gif";     // set the icon image
    lotLoc.shadow = "";                                 // no shadow
    lotLoc.iconSize = new GSize(24, 24);                // set the size
    var markerOptions = { icon: lotLoc };               

    $.post(opts.postScript, {action: 'drawlotLoc', id: id}, function(data) {

        var markers = new Array();
        // lotLoc[x].description
        // lotLoc[x].lat
        // lotLoc[x].lng
        // lotLoc[x].nighbourhood
        // lotLoc[x].lot
        var lotLoc = $.evalJSON(data);

        for(var i=0; i<lotLoc.length; i++) {
            var spLat = parseFloat(lotLoc[i].lat);
            var spLng = parseFloat(lotLoc[i].lng);

            var latlng = new GLatLng(spLat, spLng)
            markers[i] = new GMarker(latlng, markerOptions);

            myMap.addOverlay(markers[i]);

            GEvent.addListener(markers[i], "click", function() {
                console.log(i);     // returning 5 in all cases. 
                                    // I _need_ this to be unique to the object being clicked.
                console.log(this);
            });
        }
    });
4

1 回答 1

1

您对闭包有疑问。您的功能看到i's last valuse。只需添加另一个闭包来修复您的错误:

for(var i=0; i<lotLoc.length; i++) {
    (function(i){
        // ...
    })(i); //run the function with i as argument
}//for
于 2010-03-13T20:58:16.857 回答