我正在尝试在 Rust 中实现一个简单的二叉搜索树,但我很难确定插入节点的问题。我正在使用以下数据结构和函数。
enum BinaryTree<T> {
Leaf(T),
Branch(T, Box<BinaryTree<T>>, Box<BinaryTree<T>>),
Null,
}
fn createBinarySearchTree(vector: Vec<int>) -> BinaryTree<int> {
fn insertNode(val: int, btree: &BinaryTree<int>) -> BinaryTree<int> {
match btree {
&Leaf(tval) if val > tval => Branch(tval, box Null, box Leaf(val)),
&Leaf(tval) if val < tval => Branch(tval, box Leaf(val), box Null),
&Branch(tval, box ref left, box ref right) if val > tval => insertNode(val,right),
&Branch(tval, box ref left, box ref right) if val < tval => insertNode(val,left),
&Null => Leaf(val),
&Leaf(lval) if val == lval => Leaf(val),
&Branch(lval, box ref left, box ref right) if val == lval => fail!("already has a node with {}", lval),
_ => Null,
}
}
let mut tree = Null;
for v in vector.iter() {
tree = insertNode(*v, &tree);
}
let immuTree = tree;
immuTree
}
fn printTree(tree: &BinaryTree<int>) {
fn innerPrint(prefix: &str, tree: &BinaryTree<int>, level: int) {
let lvDesc = format!("lv {}", level);
match tree {
&Leaf(val) => println!("{}-{} leaf: {}", lvDesc, prefix, val),
&Branch(val, box ref left, box ref right) => {
println!("{}-{} node: {}", lvDesc, prefix, val);
innerPrint("left branch <-", left, level + 1);
innerPrint("right branch ->", right, level + 1);
},
&Null => println!("end"),
}
}
innerPrint("root", tree, 0);
}
在调用printTree(&createBinarySearchTree(vec![43,2,45,7,72,28,34,33]))
树时只会打印出来33,34
,不幸的是我无法调试,因为使用调试信息进行编译会导致编译器错误。此外,当我在插入时匹配分支时,我尝试返回一个分支,但这需要我以我无法理解的方式克隆叶子/授予所有权。所以任何帮助将不胜感激
干杯