我已经完成了解决这个问题的第一步,我想我会分享一下,以防其他人在未来的某个时候寻找。我以上面的答案为基础,创建了一个通用的线性方程列表,可以用来确定大致的年级水平。首先必须更正这些值以使其更线性。这没有考虑到无效区域,但我可能会重新考虑。方程类:
public class GradeLineEquation
{
// using form y = mx+b
// or y=Slope(x)=yIntercept
public int GradeLevel { get; set; }
public float Slope { get; set; }
public float yIntercept { get; set; }
public float GetYGivenX(float x)
{
float result = 0;
result = (Slope * x) + yIntercept;
return result;
}
public GradeLineEquation(int gradelevel,float slope,float yintercept)
{
this.GradeLevel = gradelevel;
this.Slope = slope;
this.yIntercept = yintercept;
}
}
这是 FryCalculator:
public class FryCalculator
{
//this class normalizes the plot on the Fry readability graph the same way a person would, by choosing points on the graph based on values even though
//the y-axis is non-linear and neither axis starts at 0. Just picking a relative point on each axis to plot the intercept of the zero and infinite scope lines
private List<GradeLineEquation> linedefs = new List<GradeLineEquation>();
public FryCalculator()
{
LoadLevelEquations();
}
private void LoadLevelEquations()
{
// load the estimated linear equations for each line with the
// grade level, Slope, and y-intercept
linedefs.Add(new NLPTest.GradeLineEquation(1, (float)0.5, (float)22.5));
linedefs.Add(new NLPTest.GradeLineEquation(2, (float)0.5, (float)20.5));
linedefs.Add(new NLPTest.GradeLineEquation(3, (float)0.6, (float)17.4));
linedefs.Add(new NLPTest.GradeLineEquation(4, (float)0.6, (float)15.4));
linedefs.Add(new NLPTest.GradeLineEquation(5, (float)0.625, (float)13.125));
linedefs.Add(new NLPTest.GradeLineEquation(6, (float)0.833, (float)7.333));
linedefs.Add(new NLPTest.GradeLineEquation(7, (float)1.05, (float)-1.15));
linedefs.Add(new NLPTest.GradeLineEquation(8, (float)1.25, (float)-8.75));
linedefs.Add(new NLPTest.GradeLineEquation(9, (float)1.75, (float)-24.25));
linedefs.Add(new NLPTest.GradeLineEquation(10, (float)2, (float)-35));
linedefs.Add(new NLPTest.GradeLineEquation(11, (float)2, (float)-40));
linedefs.Add(new NLPTest.GradeLineEquation(12, (float)2.5, (float)-58.5));
linedefs.Add(new NLPTest.GradeLineEquation(13, (float)3.5, (float)-93));
linedefs.Add(new NLPTest.GradeLineEquation(14, (float)5.5, (float)-163));
}
public int GetGradeLevel(float avgSylls,float avgSentences)
{
// first normalize the values given to cartesion positions on the graph
float x = NormalizeX(avgSylls);
float y = NormalizeY(avgSentences);
// given x find the first grade level equation that produces a lower y at that x
return linedefs.Find(a => a.GetYGivenX(x) < y).GradeLevel;
}
private float NormalizeY(float avgSentenceCount)
{
float result = 0;
int lower = -1;
int upper = -1;
// load the list of y axis line intervalse
List<double> intervals = new List<double> {2.0, 2.5, 3.0, 3.3, 3.5, 3.6, 3.7, 3.8, 4.0, 4.2, 4.3, 4.5, 4.8, 5.0, 5.2, 5.6, 5.9, 6.3, 6.7, 7.1, 7.7, 8.3, 9.1, 10.0, 11.1, 12.5, 14.3, 16.7, 20.0, 25.0 };
// find the first line lower or equal to the number we have
lower = intervals.FindLastIndex(a => ((double)avgSentenceCount) >= a);
// if we are not over the top or on the line grab the next higher line value
if(lower > -1 && lower < intervals.Count-1 && ((float) intervals[lower] != avgSentenceCount))
upper = lower + 1;
// set the integer portion of the respons
result = (float)lower;
// if we have an upper limit calculate the percentage above the lower line (to two decimal places) and add it to the result
if(upper != -1)
result += (float)Math.Round((((avgSentenceCount - intervals[lower])/(intervals[upper] - intervals[lower]))),2);
return result;
}
private float NormalizeX(float avgSyllableCount)
{
// the x axis is MUCH simpler. Subtract 108 and divide by 2 to get the x position relative to a 0 origin.
float result = (avgSyllableCount - 108) / 2;
return result;
}
}