This question is an extension of this question. I understand that due to push_back()
new memory allocation takes place and the address of the first element of std::vector v
changes but should not std::vector v2
change its address accordingly?
#include <memory>
#include <iostream>
#include <vector>
#include <functional>
int main()
{
std::vector<int> v;
std::vector<std::reference_wrapper<int>> v2;
for (int i=0; i<3; ++i)
{
int b = i;
v.push_back(b);
v2.push_back(v.back());
std::cout << "org: " << std::addressof(v[0]) << std::endl;
std::cout << "ref: " << std::addressof(v2[0].get()) << std::endl;
}
return 0;
}
Output:
org: 0x605010
ref: 0x605030
org: 0x605050
ref: 0x605010
org: 0x605030
ref: 0x605070