我正在尝试使用 grunt 和 almond 创建一个 requirejs 优化配置。这是配置:
requirejs:
build:
options:
almond: true
dir: 'build'
appDir: ''
baseUrl: '../client'
wrap: true
include: '../client/main'
keepBuildDir: true
paths:
underscore: 'client/vendor/underscore'
jquery : 'client/vendor/jquery'
backbone : 'client/vendor/backbone'
文件夹结构:
错误:
C:\Users\User\Documents\Source\Project>grunt requirejs
Running "requirejs:build" (requirejs) task
>> Error: ENOENT, no such file or directory
>> 'C:\Users\User\Documents\Source\Project\build\models\MenuItem.js'
>> In module tree:
>> ../client/main
Warning: RequireJS failed. Use --force to continue.
Main.js 代码(用咖啡脚本编写)
requirejs.config(
baseUrl: "client"
shim:
'backbone':
deps: ['jquery']
exports: 'Backbone'
'jquery':
exports: '$'
'underscore':
exports: '_'
paths:
jquery: 'vendor/jquery-1.11.0'
underscore: 'vendor/underscore'
backbone: 'vendor/backbone'
)
define 'start', ()->
window.types =
Models: {}
Collections: {}
Views: {}
null
require ['models/MenuItem', 'views/MenuItem'], (MenuItemModel, MenuItemView)->
view = new MenuItemView(
new MenuItemModel(),
"#app",
'first'
)
view.render();
null
我想以不需要 requirejs 的方式将分布在多个 js 文件中的整个项目编译成一个文件。我正在尝试使用 almond js 执行此操作,但构建任务不会查找相对于引用文件路径的引用文件。请帮助我进行正确的配置。