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我有 WCF 服务,我们必须生成消费免费信用的客户记录。我已经生成了这些记录,但现在具有相同登录 ID 的客户在记录中重复出现。我不想再次显示登录 ID,但想显示他们拨打的所有号码。这是我的观点的代码

         @model IEnumerable<MyYello.Admin.Models.CallHistory>

  @{ViewBag.Title = "UsersWhoHaveConsumedFreeCredit";
  Layout = "~/Views/Shared/_Layout.cshtml";
    }

  <h2>Users Who Have Consumed Free Credit</h2>
  <table class="table table-striped table-bordered tablesorter" style="display: block">
   <thead>
    <tr>
        <th>Login</th>
        <th>FirstName</th>
        <th>LastName</th>
        <th>Email</th>
        <th>Country</th>
        <th>Phone</th>
        <th>TarrifDesc</th>
        <th>CalledNum</th>
        <th>CallStart</th>
        <th>CallEnd</th>
    </tr>
    </thead>
    <tbody>
    @foreach (var item in Model)
    {
        <tr>
            <td>@item.Login</td>
            <td>@item.FirstName</td>
            <td>@item.LastName</td>
            <td>@item.Email</td>
            <td>@item.Country</td>
            <td>@item.Phone</td>
            <td>@item.TariffDescription</td>    
        </tr>    
    }
    @if (!Model.Any())
    {
        <tr>
            <td colspan="14">No Record Found</td>
        </tr>
    }
   </tbody>
 </table>

只需要一个想法

4

1 回答 1

0

你应该先按用户登录分组。这是一个例子:

@foreach (var group in Model.GroupBy(history => history.Login))
{
    var item = group.First();
    <tr>
        <td>@item.Login</td>
        <td>@item.FirstName</td>
        <td>@item.LastName</td>
        <td>@item.Email</td>
        <td>@item.Country</td>
        <td>@string.Join(" - ", group.Select(history => history.Phone))</td>
        <td>@item.TariffDescription</td>
    </tr>
}
于 2014-06-20T08:29:15.983 回答