1

我正在尝试在对话框中获取 EditText 的值。以下代码中的“*”行,safeNameEditText 为空;我假设是因为“findVeiwById”正在搜索“AlertDialog.OnClickListener”的上下文;如何获取/更改“findViewById”调用的上下文?

 protected Dialog onCreateDialog(int id) {
  AlertDialog.Builder builder = new AlertDialog.Builder(this);

  switch(id){
   case DIALOG_NEW_SAFE:
    builder.setTitle(R.string.news_safe);
    builder.setIcon(android.R.drawable.ic_menu_add);

    LayoutInflater factory = LayoutInflater.from(this); 
    View newSafeView = factory.inflate(R.layout.newsafe, null);

    builder.setView(newSafeView);
    builder.setPositiveButton(R.string.ok, new AlertDialog.OnClickListener(){
     public void onClick(DialogInterface dialog, int which) {
 *     EditText safeNameEditText = (EditText) findViewById(R.id.new_safe_name);
      String safeName = safeNameEditText.getText().toString();
      Log.i(LOG, safeName);
      setSafeDao(safeName);
     }     
    });

    builder.setNegativeButton(R.string.cancel, new AlertDialog.OnClickListener(){
     public void onClick(DialogInterface dialog, int which) {
      dialog.dismiss();
     } 
    });
    return(builder.create());
   default:
    return(null);
  }
 }
4

2 回答 2

3

我认为您需要引用该视图,因为对话框看不到该 edittext 字段:

EditText safeNameEditText = (EditText) newSafeView.findViewById(R.id.new_safe_name);

于 2010-03-12T15:47:12.507 回答
0

不是您问题的真正答案,但这将帮助您实现您想要做的事情......

final EditText safeNameEditText = (EditText) findViewById(R.id.new_safe_name);
builder.setPositiveButton(R.string.ok, new AlertDialog.OnClickListener(){
public void onClick(DialogInterface dialog, int which) {
    String safeName = safeNameEditText.getText().toString();
    Log.i(LOG, safeName);
    setSafeDao(safeName);
}     
});
于 2010-03-12T06:22:35.877 回答