c# - 在 XmlReader 中解析 XML 元素

Question

我正在构建一个需要通过 XML 提要运行的应用程序，但在获取某些元素时遇到了一些麻烦。

我正在使用Twitter 提要并希望浏览所有<item>元素。我可以很好地连接并从提要中获取内容，但我不知道item在循环时如何仅选择元素reader.Read();。

谢谢你的帮助！

Answer 1

最简单的方法是使用 XPath。要遵循的示例。

 string xml = @"<?xml version=""1.0"" encoding=""UTF-8""?>
<rss version=""2.0"">
    <channel>
    <title>Twitter public timeline</title>
    <link>http://twitter.com/public_timeline</link>
    <description>Twitter updates from everyone!</description>
    <language>en-us</language>
    <ttl>40</ttl>

    <item>
      <title>yasu_kobayashi: rTwT: @junm : yayaya</title>
      <description>yasu_kobayashi: rTwT: @junm : yayaya</description>
      <pubDate>Tue, 28 Oct 2008 12:04:48 +0000</pubDate>
      <guid>http://twitter.com/yasu_kobayashi/statuses/978829930</guid>
      <link>http://twitter.com/yasu_kobayashi/statuses/978829930</link>

    </item><item>
      <title>FreeGroup: WikiFortio - foobar http://tinyurl.com/5gvttf</title>
      <description>FreeGroup: WikiFortio - foobar
      http://tinyurl.com/5gvttf</description>
      <pubDate>Tue, 28 Oct 2008 12:04:47 +0000</pubDate>
      <guid>http://twitter.com/FreeGroup/statuses/978829929</guid>
      <link>http://twitter.com/FreeGroup/statuses/978829929</link>

    </item></channel></rss>
        ";
            XPathDocument doc = new XPathDocument(new StringReader(xml));
            XPathNavigator nav = doc.CreateNavigator();

            // Compile a standard XPath expression

            XPathExpression expr;
            expr = nav.Compile("/rss/channel/item");
            XPathNodeIterator iterator = nav.Select(expr);

            // Iterate on the node set

            try
            {
                while (iterator.MoveNext())
                {
                    XPathNavigator nav2 = iterator.Current.Clone();
                    nav2.MoveToChild("title","");
                    Console.WriteLine(nav2.Value);
                    nav2.MoveToParent();
                    nav2.MoveToChild("pubDate","");
                    Console.WriteLine(nav2.Value);

                }
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
            Console.ReadKey();

这是 jan 的工作方法

        XmlDocument doc2 = new XmlDocument();
        doc2.LoadXml(xml);
        XmlNode root = doc2.DocumentElement;

        foreach (XmlNode item in root.SelectNodes(@"/rss/channel/item"))
        {
            Console.WriteLine(item.SelectSingleNode("title").FirstChild.Value);
            Console.WriteLine(item.SelectSingleNode("pubDate").FirstChild.Value);
        }

Answer 2

替代：

// starts as in Vinko Vrsalovic 's answer
// and not including decent eror handling
XmlDocument doc = new XmlDocument(new StringReader(xml)); 

foreach (XmlNode item in doc.SelectNodes(@"/rss/channel/item"))
{
  Console.WriteLine(item.SelectSingleNode("title").Value);
  Console.WriteLine(item.SelectSingleNode("pubDate").Value);
}

我不知道这段代码是较慢还是不好的做法。请发表评论。

我发现它比使用 Navigator 和 Iterator 的另一个更具可读性。

Edit: I use an XmlDocument. An XPathDocument as in Vinko Vrsalovic 's answer doesn't support this way of working, but is a lot faster: (MSDN)