0

我有这样的形式:

class TitlePropose(forms.Form):
    title = forms.CharField(max_length=128)
    code= forms.CharField(max_length=32)
    def __init__(self, contest, *args, **kwargs):
        super(TitlePropose, self).__init__(*args, **kwargs)
        self.helper = FormHelper()
        self.helper.form_id = self.__class__.__name__.lower()
        self.helper.form_action = ''
        self.helper.layout = Layout(,
            Field('title'),
            Field('code'),
        )


    def clean_title(self):
        if OtherModel.objects.filter(contest=contest, title=self.cleaned_data['title']).count() > 0:
            raise forms.ValidationError("Title unavailable")
        else:
            return self.cleaned_data['title']

我尝试从 clean_title 方法访问变量“contest”,但没有任何成功。我在表单类构造函数中传递这个变量:

#contest is just some object
new_title_form = TitlePropose(contest=contest.uuid)

有什么建议,我怎样才能在 clean_title 中访问“竞赛”?

4

1 回答 1

3

这是标准的 Python 类的东西。如果您想存储一个对象以便其他方法可以访问它,您可以通过将其添加到self.

def __init__(self, *args, **kwargs):
    self.contest = kwargs.pop('contest')
    super(TitlePropose, self).__init__(*args, **kwargs)

def clean_title(self):
    if OtherModel.objects.filter(contest=self.contest, ...
于 2014-06-16T20:21:13.913 回答