我在 Obj-C 中有以下方法:
- (RACSignal *)fetchCurrentConditionsForLocation:(CLLocationCoordinate2D)coordinate {
NSString *urlString = [NSString stringWithFormat:@"http://api.openweathermap.org/data/2.5/weather?lat=%f&lon=%f&units=metric", coordinate.latitude, coordinate.longitude];
NSURL *url = [NSURL URLWithString:urlString];
return [[self fetchJSONFromURL:url] map:^(NSDictionary *json) {
return [MTLJSONAdapter modelOfClass:[WXCondition class] fromJSONDictionary:json error:nil];
}];
}
我转换为 Swift:
func fetchJSONFromURL(url: NSURL) -> RACSignal {
}
func fetchCurrentConditionsForLocation(coordinate: CLLocationCoordinate2D) -> RACSignal {
let urlString = NSString(format: "http://api.openweathermap.org/data/2.5/weather?lat=%f&lon=%f&units=metric", coordinate.latitude, coordinate.longitude)
let url = NSURL.URLWithString(urlString)
// Convert to Swift?
return [[self fetchJSONFromURL:url] map:^(NSDictionary *json) {
return [MTLJSONAdapter modelOfClass:[WXCondition class] fromJSONDictionary:json error:nil];
}];
}
在 Swift 中使用此地图时遇到问题:
return [[self fetchJSONFromURL:url] map:^(NSDictionary *json) {
return [MTLJSONAdapter modelOfClass:[WXCondition class] fromJSONDictionary:json error:nil];
}];
一切都在正确编译,但是有没有更好的方法呢?