swift - 'inout String' 不能转换为 'UnsafePointer'

Question

我正在使用一个需要UnsafePointer<String>.

如何UnsafePointer<String>从字符串中获取一个？

尝试&someString给了我错误：

'inout String' is not convertible to 'UnsafePointer<String>'

Answer 1

&someString创建一个CMutablePointer<String>.

要将其转换为UnsafePointer，最简单的解决方案是调用特殊函数：

withUnsafePointer(&someString) { unsafePointer in
    //do something with the unsafePointer
}