ios - Swift 中的 CGSize sizeWithAttributes

Question

在 Objective-C 中，我可以使用：

    CGSize stringsize =
     [strLocalTelefone sizeWithAttributes:@{NSFontAttributeName:[UIFont systemFontOfSize:14.0f]}];

但是在 Swift 语言中，我没有找到任何解决这种情况的方法。

有什么帮助吗？

Answer 1

我所做的是这样的：

迅捷5.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [.font: UIFont.systemFont(ofSize: 14)])

---

迅捷4.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [NSAttributedStringKey.font: UIFont.systemFont(ofSize: 14)])

---

迅速 3

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 14.0)])

---

迅捷 2.x

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

Answer 2

只需使用显式转换：

var stringsize = (strLocalTelefone as NSString).sizeWithAtt...

否则你也可以桥接它：
Swift 的更高版本不再支持桥接。

var strLocalTelefone = "some string"
var stringsize = strLocalTelefone.bridgeToObjectiveC().sizeWithAttributes([NSFontAttributeName:UIFont.systemFontOfSize(14.0)])

这个答案至少值得一看，因为它突出了两种方法之间的潜在差异。

Answer 3

只有一条线的解决方案：

yourLabel.intrinsicContentSize.width用于 Objective-C / Swift

即使您的标签文本具有自定义文本间距，这也将起作用。

Answer 4

您也可以使用这段代码，它更容易，您不必为了获取 NSString 对象而创建新变量：

var stringToCalculateSize:String = "My text"
var stringSize:CGSize = (stringToCalculateSize as NSString).sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

Answer 5

在 xCode 6.3 上，这是您现在需要做的：

    let font:AnyObject = UIFont(name: "Helvetica Neue", size: 14.0) as! AnyObject
    let name:NSObject = NSFontAttributeName as NSObject
    let dict = [name:font]
    let textSize: CGSize = text.sizeWithAttributes(dict)

Answer 6

在 xCode 8.0 上，这是您现在需要做的： let charSize = string.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 20)])