2

我有一个非常简单的案例类,它是一个更大的案例类的一部分。

case class PublisherStatus(status: String)
case class Publisher(id: Option[BSONObjectID], name: String, status: PublisherStatus, keywords: List[String], updatedAt: Option[DateTime], outputChannelIP: String, outputChannelName: String)

我已经为它定义了 BSON Reader 和 Writer,如下所示。

  implicit object StatusBSONReader extends BSONDocumentReader[PublisherStatus] {
    def read(doc: BSONDocument): PublisherStatus =
      PublisherStatus(
        doc.getAs[String]("status").get
      )
  }

  implicit object StatusBSONWriter extends BSONDocumentWriter[PublisherStatus] {
    def write(status: PublisherStatus): BSONDocument =
      BSONDocument(
        "status" -> status.status)
  }

但是,当我尝试执行以下操作时,会出现编译错误。

  def updateState(id: String, s: String) {
    import models.PublisherBSONWriter._
    implicit val statusWrites = Json.writes[PublisherStatus]
    val objectId = new BSONObjectID(id)
    val status = PublisherStatus(s)
    val modifier = BSONDocument("$set" -> status)

    val updateFuture = collection.update(BSONDocument("_id" -> objectId), modifier)

  }

错误 -

could not find implicit value for parameter writer: reactivemongo.bson.BSONWriter[models.PublisherStatus, _ <: reactivemongo.bson.BSONValue]
[error]     val modifier = BSONDocument("$set" -> status)
[error]                                        ^
[error] one error found
[error] (compile:compile) Compilation failed
4

1 回答 1

5

的 reader 和 writerPublisherStatus不应该是BSONDocumentReaderand BSONDocumentWriter,而应该是BSONReaderand BSONWriter

或者为了让事情变得更简单,使用BSONHandler. 类似的东西

implicit val bson = new BSONHandler[BSONString, PublisherStatus] {
  def read(bson: BSONString) = PublisherStatus(bson.value)
  def write(status: PublisherStatus) = BSONString(status.status)
}
于 2014-06-09T05:23:04.183 回答