10

我有一堆 XSD.exe 生成的数据协定类,它们对于所有可选元素都有一对 C# 属性,例如

int Amount {get; set;}
bool isAmountSpecified {get; set;}

在映射竞技场的另一边,我有一个可以为空的 int 像

int? Amount {get; set;}

理想情况下,我希望 AutoMapper 能够识别此类模式并知道如何在两个方向上映射事物,而无需为每个单独的属性指定映射。这可能吗?

4

3 回答 3

2

好的,昨天我与 AutoMapper 的作者 Jimmy Bogard 进行了简短的讨论,基本上我正在寻找的内容目前是不可能的。对此类约定的支持将在未来的某个时间实施(如果我理解正确的话:))。

于 2010-03-10T06:24:47.097 回答
1

老实说,我不知道 AutoMapper 是否会这样做(因为我不经常使用 AutoMapper),但我知道 protobuf-net 支持这两种模式,因此您可以使用Serializer.ChangeType<,>(obj)它们在它们之间切换。

但是,当前版本非常依赖于成员的属性(例如[XmlElement(Order = n)]) - 我不知道这是否会导致问题?正在进行的版本支持原版类型(没有属性),但这还不完整(但很快)。

例子:

[XmlType]
public class Foo
{
    [XmlElement(Order=1)]
    public int? Value { get; set; }
}
[XmlType]
public class Bar
{
    [XmlElement(Order = 1)]
    public int Value { get; set; }
    [XmlIgnore]
    public bool ValueSpecified { get; set; }
}
static class Program
{
    static void Main()
    {
        Foo foo = new Foo { Value = 123 };
        Bar bar = Serializer.ChangeType<Foo, Bar>(foo);
        Console.WriteLine("{0}, {1}", bar.Value, bar.ValueSpecified);

        foo = new Foo { Value = null };
        bar = Serializer.ChangeType<Foo, Bar>(foo);
        Console.WriteLine("{0}, {1}", bar.Value, bar.ValueSpecified);

        bar = new Bar { Value = 123, ValueSpecified = true };
        foo = Serializer.ChangeType<Bar, Foo>(bar);
        Console.WriteLine(foo.Value);

        bar = new Bar { Value = 123, ValueSpecified = false };
        foo = Serializer.ChangeType<Bar, Foo>(bar);
        Console.WriteLine(foo.Value);
    }
}
于 2010-03-09T12:20:36.037 回答
-1

这是如何将具有 *Specified 属性(源)的模型映射到具有可为空属性(目标)的模型的示例。我已经为所有成员配置了 Condition 方法,它将检查源属性是否具有相应的 *Specified 属性,如果有,那么它将检查它的值。如果 *Specified 属性返回false,则不满足条件并且将跳过映射。

您可以在其他方向上执行相同操作,但您必须设置它而不是读取 *Specified 属性值。

public void Configure(IMapperConfigurationExpression cfg)
{
    cfg.CreateMap<Source, Destination>()
        .ForAllOtherMembers(opt => opt.PreCondition((srcObj, context) => IsSpecified(srcObj, context, opt)));
}

public static bool IsSpecified<TSource, TDestination, TMember>(TSource source, ResolutionContext context, IMemberConfigurationExpression<TSource, TDestination, TMember> opt)
{
    var dstMemberPropertyInfo = opt.DestinationMember as PropertyInfo;

    // if destination member not nullable, then assume that source member won't have *Specified property
    if (!IsNullableType(dstMemberPropertyInfo.PropertyType))
        return true;

    var config = context.Mapper.ConfigurationProvider;
    var map = config.FindTypeMapFor<TSource, TDestination>();
    var propertyMap = map.PropertyMaps.FirstOrDefault(x => x.DestinationMember.Name == opt.DestinationMember.Name);
    var sourceMembers = new Queue<MemberInfo>(propertyMap.SourceMembers);
    var srcParentType = typeof(TSource);
    var srcParentObj = source as object;

    // get the source parent instance
    while (sourceMembers.Count > 1) // the last item in queue is the SourceMember itself
    {
        var srcParentPropertyInfo = sourceMembers.Dequeue() as PropertyInfo;
        srcParentType = srcParentPropertyInfo.PropertyType;
        srcParentObj = srcParentPropertyInfo.GetValue(srcParentObj);

        // the source parent is not defined, so we can skip this mapping
        if (srcParentObj == null)
            return false;
    }

    var srcMemberSpecifiedPropName = propertyMap.SourceMember.Name + "Specified";
    var srcMemberSpecifiedProp = srcParentType.GetProperty(srcMemberSpecifiedPropName);

    // if there is no *Specified property, then assume value is specified
    return srcMemberSpecifiedProp == null || (bool)srcMemberSpecifiedProp.GetValue(srcParentObj);
}

private bool IsNullableType(Type type) => IsGenericType(type, typeof(Nullable<>));

private bool IsGenericType(Type type, Type genericType) => IsGenericType(type) && type.GetGenericTypeDefinition() == genericType;

private bool IsGenericType(Type type) => type.GetTypeInfo().IsGenericType;
于 2020-04-15T13:10:31.600 回答