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假设我有一个文本文件text.txt，其中包含几行使用单个空格（而不是制表符）缩进的文本，例如：

My folder1/
  My folder2/ 
  My folder3/ 
     file1.md
My folder4/

例如，实际的目录模板可能如下所示：

Proposal/
 rules/
 proposal/
  document.tex
  figs/
  tabs/
  ref/
  log/
  src/
   master.r
   crdat/
   andat/
  temp/
  data/
   raw/
   clean/

Admin/
  budget/
  contract/
  invoices/
  receipts/
  team/
   hiring/
   vitae/
  gantt/  
  forms/
  misc/

Study/
 document.tex
 figs/
 tabs/
 ref/
 log/
 src/
  master.r
  crdat/
  andat/
 temp/
 data/
  raw/
  clean/

Dissemination/
 presentations/
  conference1/
   submission.md
   slides.tex
   notes.md
   admin/
    registration/
    travel/
    receipts/
    program/
    forms/
  conference2/
 manuscripts/
  journal1/
   submission/
    letter_v1.tex
    manuscript_v1.pdf
    replication_v1.zip
    comments/
     reviewer1.txt
   R&R/
    letter_v2.tex
    manuscript_v2.tex
    diff.tex
    replication_v2.zip
  journal2/

master_notes.md
TODOs.md
README.md

本质上，该文件是目录结构的模板。该模板可由用户设置。她可以为不同的项目使用不同的模板，并且名称是通用的。唯一的限制是层次结构是使用空格建立的，并且文件夹以正斜杠结尾。

我想编写一个函数，它将任何这样的目录模板作为输入，并在您当前的工作目录中创建一个目录结构。伪代码如下：

lines <- readLines(text.txt)
last.indent <- 0
for (i in lines) {
  Create directory structure by looking at leading character and last characters (folders end in /)
  using dir.create(i) or file.create(i)
}
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1 回答 1

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我怀疑你实际上正在做一些更复杂的事情。在这种情况下，这可能不起作用：

library(qdap); library(reports)

x <- readLines(n=13) ## you'd read this in from a file I assume
My folder1/
  My folder2/ 
  My folder3/ 
     file1.md
My folder4/
My folder1b/
  My folder2/ 
  My folder3/ 
     file1.zip
My folder1c/
  My folder2/ 
  My folder3/ 
     file1.pdf

## You didn't ask for this but this keeps the direcories contained
new <- folder(new)
setwd(new)

dirs <- which(substring(x, 1, 1) != " ")

lens <- lapply(seq_along(dirs), function(i) {
    dirs[i]:c(tail(dirs - 1, -1), length(x))[i]
})

paths <- split(x, rep(1:length(dirs), sapply(lens, length)))

path <- sapply(paths, function(x) paste(Trim(x), collapse=""))
is.dir <- sapply(path, function(x) substring(x, nchar(x))) == "/"

lapply(seq_along(is.dir), function(i){
     out <- folder(folder.name =ifelse(is.dir[i], 
         path[i], dirname(path[i])))
     if(!is.dir[i]) {
         cat("", file = paste0(path[i], "_hold_.txt"))
     }
})
于 2014-06-06T02:59:07.370 回答