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我正在使用具有高级服务和 Visual Studio 2013 更新 2 的 SQL Server Express 2012。我已将示例简化为核心。我的数据库中有下表：

CREATE TABLE [dbo].[Realty]
(
[Id] [int] IDENTITY(1,1) NOT NULL,
...
...
[RankingBonus] [int] NOT NULL,
[Ranking]  AS ([Id]+[RankingBonus]) PERSISTED NOT NULL,
...
)

在此表上具有全文表功能：

CREATE FUNCTION [dbo].[GetFilteredRealtyFulltext]
(@fulltextcriteria nvarchar(4000))
RETURNS TABLE
AS
RETURN (SELECT 
realty.Id AS realtyId,
...
realty.Ranking, --THIS IS IMPORTANT FOR THE QUIESTION!
...,
( COALESCE(ftR.Rank,0) + COALESCE(ftObec.Rank,0) + COALESCE(ftOkres.Rank,0) + COALESCE(ftpobvod.Rank,0)) AS FtRank

FROM realty
--these joins and where conditions are not important for this stackoverflow question
--this only shows why I use table function with return table
--it is because this is the only way I found how to generate LINQ to SQL with fulltext as IQueryable<T>
JOIN Category ON realty.CategoryId = Category.Id
LEFT JOIN ruian_cobce ON realty.cobceId = ruian_cobce.cobce_kod
LEFT JOIN ruian_obec ON realty.obecId = ruian_obec.obec_kod
LEFT JOIN okres ON realty.okresId = okres.okres_kod
LEFT JOIN ExternFile ON realty.Id = ExternFile.ForeignId AND ExternFile.IsMain = 1 AND ExternFile.ForeignTable = 5
INNER JOIN Person ON realty.OwnerId = Person.Id
Left JOIN CONTAINSTABLE(Realty, *, @fulltextcriteria) ftR ON realty.Id = ftR.[Key] 
Left JOIN CONTAINSTABLE(ruian_obec, *, @fulltextcriteria) ftObec ON realty.obecId = ftObec.[Key] 
Left JOIN CONTAINSTABLE(Okres, *, @fulltextcriteria) ftOkres ON realty.okresId = ftOkres.[Key]
Left JOIN CONTAINSTABLE(pobvod, *, @fulltextcriteria) ftpobvod ON realty.pobvodId = ftpobvod.[Key]
WHERE Person.ConfirmStatus = 1
AND ( COALESCE(ftR.Rank,0) + COALESCE(ftObec.Rank,0) + COALESCE(ftOkres.Rank,0) + COALESCE(ftpobvod.Rank,0))  > 0
)
GO

当我将函数 GetFilteredRealtyFulltext 放入 DBML 时，设计器将列 Ranking 生成为Nullable int

[global::System.Data.Linq.Mapping.ColumnAttribute(Storage="_Ranking", DbType="Int")]
public System.Nullable<int> Ranking
{
  get
  {
    return this._Ranking;
  }
  set
  {
    if ((this._Ranking != value))
    {
       this._Ranking = value;
    }
  }
}

我希望它应该只生成整数：

[global::System.Data.Linq.Mapping.ColumnAttribute(Storage="_Ranking", DbType="Int NOT NULL"")]
public int Ranking
{
  get
  {
    return this._Ranking;
  }
  set
  {
    if ((this._Ranking != value))
    {
       this._Ranking = value;
    }
  }
}

DBML 文件中正确生成了表格 Realty，Ranking 只是整数，但表格函数生成错误。它有什么问题？

更新：

链接问题进入问题的核心。

4

1 回答 1

1

问题是 SQL Server 认为函数中的Ranking列GetFilteredRealtyFulltext可以为空，即使基础表列创建为NOT NULL. 您可以通过对数据库运行以下查询来查看这一点：

select 
o.name ObjectName,
c.name ColumnName,
c.is_nullable ColumnIsNullable
from 
sys.all_objects o 
inner join 
sys.all_columns c 
on 
o.object_id = c.object_id 
where 
o.[name] = 'GetFilteredRealtyFulltext'

我发现如果你创建一个基于 Realty 表的视图，SQL Server 会做同样的事情。谷歌搜索没有找到任何权威的答案，但在数据库管理员站点上确实导致了类似的问题。这导致了这个SO 讨论，这让我尝试使用ISNULL. ISNULL一旦我从 DBML 文件中删除了前一个函数并重新添加它，使用下面示例中的hack 可以在 DBML 文件中提供正确的列定义。

需要强制计算列NotNullable：

CREATE TABLE [dbo].[Realty]
(
[Id] [int] IDENTITY(1,1) NOT NULL,
...
...
[RankingBonus] [int] NOT NULL,
[Ranking]  AS ISNULL([Id]+[RankingBonus], 0) PERSISTED NOT NULL,
...
)

然后强制函数也不能为空：

CREATE FUNCTION [dbo].[GetFilteredRealtyFulltext]
(@fulltextcriteria nvarchar(4000))
RETURNS TABLE
AS
RETURN (SELECT 
realty.Id AS realtyId,
realty.RankingBonus,
ISNULL(realty.Ranking, 0) as Ranking  --ISNULL hack
FROM realty
)
GO
于 2014-06-08T05:52:55.863 回答