php - 使用 IntlDateFormatter 转换非公历日期

Question

我应该如何使用IntlDateFormatter. 我想"1392-01-02"从转换persian为islamic日历。我尝试了以下代码，但它没有转换日历：

$formatter = IntlDateFormatter::create('en_US@calendar=persian', IntlDateFormatter::FULL,
    IntlDateFormatter::FULL, 'Asia/Tokyo',IntlDateFormatter::TRADITIONAL,'yy-MM-dd');
$formatter->setCalendar(IntlDateFormatter::GREGORIAN);
echo $formatter->format($formatter->parse("1392-2-31"));

Answer 1

将要转换的时间定义为实例，IntlCalendar并使用其set($year,$month,$day)方法设置日期。

$time = IntlCalendar::createInstance("Asia/Tokyo", "en_US@calendar=persian");
$time->set(1392,2,31);

//alternative way to define time using parse

/**
These constants are used to specify different formats in the constructor for DateType 
and TimeType.

IntlDateFormatter::NONE (integer)
Do not include this element
IntlDateFormatter::FULL (integer)
Completely specified style (Tuesday, April 12, 1952 AD or 3:30:42pm PST)
IntlDateFormatter::LONG (integer)
Long style (January 12, 1952 or 3:30:32pm)
IntlDateFormatter::MEDIUM (integer)
Medium style (Jan 12, 1952)
IntlDateFormatter::SHORT (integer)
Most abbreviated style, only essential data (12/13/52 or 3:30pm)
*/

$fmt = new IntlDateFormatter(
    'en_US@calendar=persian',
    IntlDateFormatter::SHORT, //date format
    IntlDateFormatter::NONE, //time format
    'Asia/Tokyo',
    IntlDateFormatter::TRADITIONAL
);

$time = $fmt->parse('3/31/1392 AP');

$formatter = IntlDateFormatter::create("en_US@calendar=islamic",
  IntlDateFormatter::FULL, 
  IntlDateFormatter::FULL,
  'Asia/Tokyo', 
  IntlDateFormatter::TRADITIONAL);

print $formatter->format($time);
//Friday, Shaʻban 13, 1434 AH at 8:52:23 AM Japan Standard Time