16

我想要一个通用的、可重用的getPosition()方法,它会告诉我从流的起点读取的字节数。理想情况下,我希望它能够与所有 InputStreams 一起使用,这样当我从不同的来源获取它们时,我就不必包装它们中的每一个。

这样的野兽存在吗?如果没有,任何人都可以推荐现有的计数实现InputStream吗?

4

4 回答 4

21

您需要遵循建立的装饰器模式java.io来实现这一点。

让我们在这里尝试一下:

import java.io.FilterInputStream;
import java.io.IOException;
import java.io.InputStream;

public final class PositionInputStream
  extends FilterInputStream
{

  private long pos = 0;

  private long mark = 0;

  public PositionInputStream(InputStream in)
  {
    super(in);
  }

  /**
   * <p>Get the stream position.</p>
   *
   * <p>Eventually, the position will roll over to a negative number.
   * Reading 1 Tb per second, this would occur after approximately three 
   * months. Applications should account for this possibility in their 
   * design.</p>
   *
   * @return the current stream position.
   */
  public synchronized long getPosition()
  {
    return pos;
  }

  @Override
  public synchronized int read()
    throws IOException
  {
    int b = super.read();
    if (b >= 0)
      pos += 1;
    return b;
  }

  @Override
  public synchronized int read(byte[] b, int off, int len)
    throws IOException
  {
    int n = super.read(b, off, len);
    if (n > 0)
      pos += n;
    return n;
  }

  @Override
  public synchronized long skip(long skip)
    throws IOException
  {
    long n = super.skip(skip);
    if (n > 0)
      pos += n;
    return n;
  }

  @Override
  public synchronized void mark(int readlimit)
  {
    super.mark(readlimit);
    mark = pos;
  }

  @Override
  public synchronized void reset()
    throws IOException
  {
    /* A call to reset can still succeed if mark is not supported, but the 
     * resulting stream position is undefined, so it's not allowed here. */
    if (!markSupported())
      throw new IOException("Mark not supported.");
    super.reset();
    pos = mark;
  }

}

InputStreams 旨在是线程安全的,因此可以自由使用同步。我玩过volatileAtomicLong位置变量,但同步可能是最好的,因为它允许一个线程在流上操作并查询它的位置而不放弃锁。

PositionInputStream is = …
synchronized (is) {
  is.read(buf);
  pos = is.getPosition();
}
于 2008-10-27T16:05:15.273 回答
15

看看Commons IO 包中的CountingInputStream。他们还收集了很多其他有用的 InputStream 变体。

于 2008-10-27T17:31:35.990 回答
2

No.InputStream旨在处理可能无限量的数据,因此计数器会妨碍您。除了将它们全部包装起来之外,您还可以对方面做一些事情。

于 2008-10-27T15:29:23.770 回答