我正在尝试通过函数获取文档的基本路径,因为我不想找到类似../folder1/folder2/mypage.php
or的路径../../../folder1/folder2/somepage.php
。
因此我尝试...
function getBaseUrl() {
// output: /myproject/index.php
$currentPath = $_SERVER['PHP_SELF'];
// output: Array ( [dirname] => /myproject [basename] => index.php [extension] => php [filename] => index )
$pathInfo = pathinfo($currentPath);
// output: localhost
$hostName = $_SERVER['HTTP_HOST'];
// output: http://
$protocol = strtolower(substr($_SERVER["SERVER_PROTOCOL"],0,5))=='https://'?'https://':'http://';
// return: http://localhost/myproject/
return $protocol.$hostName.$pathInfo['dirname']."/";
}
然后我给写代码...
$base = getBaseUrl();
require_once $base.'_include/db/qry.php';
require_once $base.'_include/db/functions.php';
两个文件qry.php
&functions.php
都在http://localhost/mysite/_include/db/
当我运行页面时,错误显示...
Warning: require_once(): http:// wrapper is disabled in the server configuration by allow_url_include=0 in C:\xampp\htdocs\mysite\_include\header.php on line 9
Warning: require_once(http://localhost/mysite/_include/db/qry.php): failed to open stream: no suitable wrapper could be found in C:\xampp\htdocs\mysite\_include\header.php on line 9
Fatal error: require_once(): Failed opening required 'http://localhost/mysite/_include/db/qry.php' (include_path='.;C:\xampp\php\PEAR') in C:\xampp\htdocs\mysite\_include\header.php on line 9
我尝试通过回显 getBaseUrl() 之类的方法echo $base;
,它显示了正确的路径,即http://localhost/mysite/
.
我应该怎么办 ?