我正在我的Facebook应用程序上添加共享功能。有关我的 iOS 应用程序的任何信息。如何让每个人都知道这句话是通过我的 iOS 应用程序共享的?请帮我....
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我可能有点晚了。希望这可以帮助。
您必须使用 Accounts 框架和 Social 框架来与您的应用程序名称共享。首先确保您在 Facebook 上正确设置了您的应用程序。然后,您可以使用 Facebook 应用 ID 通过您的应用分享您的帖子。
这是一个示例代码,向您展示如何将 Accounts 框架与 Social Framework 一起使用:
ACAccountType * facebookAccountType = [self.accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierFacebook];
// At first, we only ask for the basic read permission
NSArray * permissions = @[@"email"];
NSMutableDictionary *dict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:@"275485699289493", ACFacebookAppIdKey, permissions, ACFacebookPermissionsKey, ACFacebookAudienceOnlyMe, ACFacebookAudienceKey, nil];
NSArray *accounts = [self.accountStore accountsWithAccountType:facebookAccountType];
//it will always be the last object with single sign on
self.facebookAccount = [accounts lastObject];
[self.accountStore requestAccessToAccountsWithType:facebookAccountType options:dict completion:^(BOOL granted, NSError *error) {
if (granted && error == nil) {
/**
* The user granted us the basic read permission.
* Now we can ask for more permissions
**/
NSArray *readPermissions = @[ @"publish_actions"];
[dict setObject:readPermissions forKey: ACFacebookPermissionsKey];
[self.accountStore requestAccessToAccountsWithType:facebookAccountType options:dict completion:^(BOOL granted, NSError *error) {
if(granted && error == nil) {
NSDictionary *parameters = @{@"message": @"This Should Work Perfectly !! "};
NSURL *feedURL = [NSURL URLWithString:@"https://graph.facebook.com/me/feed"];
SLRequest *feedRequest = [SLRequest
requestForServiceType:SLServiceTypeFacebook
requestMethod:SLRequestMethodPOST
URL:feedURL
parameters:parameters];
feedRequest.account = self.facebookAccount;
[feedRequest performRequestWithHandler:^(NSData *responseData,
NSHTTPURLResponse *urlResponse, NSError *error)
{
// Handle response
}];
} else {
NSLog(@"error is: %@",[error description]);
}
}];
} else {
NSLog(@"error is: %@",[error description]);
}
}];
}
于 2014-07-04T12:40:16.120 回答