2

我在想办法对项目 xslt 1.0 进行分组时遇到了麻烦。我有一个类似于下面的源 xml:

<client name="client A">
    <project name = "project A1"/>
    <project name = "project A2"/>
    <project name = "project A3"/>
    <project name = "project A4"/>
</client>
<client name="client B">
    <project name = "project B1"/>
    <project name = "project B2"/>
</client>
<client name="client C">
    <project name = "project C1"/>
    <project name = "project C2"/>
    <project name = "project C3"/>
</client>

我想选择所有项目,对它们进行排序,然后将每 3 个项目组合在一个范围内,如下例所示:

<boundle>
  <project name="project A1">
  <project name="project A2">
  <project name="project A3">
</boundle>
<boundle>
  <project name="project A4">
  <project name="project B1">
  <project name="project B2">
</boundle>
<boundle>
  <project name="project C1">
  <project name="project C2">
  <project name="project C3">
</boundle>

目前这样做我正在使用打开一个边界标签并稍后关闭它。你能想出更好的解决方案吗?

4

2 回答 2

4

无需分组。

<xsl:param name="perGroup" select="3" />

<xsl:variable name="allProjects" select="/client/project" />

<xsl:template match="/">
  <xsl:apply-templates select="$allProjects" mode="counted" />
</xsl:template>

<xsl:template match="project" mode="counted">
  <xsl:if test="position() mod $perGroup = 1">
    <xsl:variable name="pos" select="position()" />
    <boundle>
      <xsl:copy-of select="$allProjects[
        position() &gt;= $pos and position() &lt; ($pos + $perGroup)
      ]" />
    </boundle>
  </xsl:template>
</xsl:template>
于 2010-03-08T09:54:31.953 回答
0

我可以推荐以下链接http://www.jenitennison.com/xslt/grouping/它帮助我弄清楚如何根据 XML 文档中的内容将各种数量的元素分组到某些类别中。

于 2012-02-19T18:59:26.317 回答