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我正在尝试运行我的第一个 openxava 应用程序。我只有一个包含 4 个字段的文件。我正在使用 Tomcat 和 Mssql 服务器。我构建项目，运行和部署一切都很好..我现在使用 jd1.7。在我尝试使用 1.8 之前，我遇到了同样的错误。

这些是我的字段：@Id @Required
private Integer kifid; @Column(length=1) 私有字符串 kisifirma;

@Column(length=1)
private String gonullumu;

@Column(length=50) 
private String tckno;

sql structure is like this :

CREATE TABLE [dbo].[sekreterya_kisifirma](
[kifid] [int] IDENTITY(1,1) NOT NULL,
[kisifirma] [char](1) NULL,
[Gonullumu] [int] NULL,
[TCKNo] [varchar](50) NULL, .....

当我尝试从浏览器访问我的模块时，这个异常来了。我觉得这应该是一个容易解决的问题。但我需要一些帮助..

org.apache.jasper.JasperException: Unable to compile class for JSP: 

An error occurred at line: 7 in the generated java file 
The import java.util.Arrays cannot be resolved

An error occurred at line: 32 in the jsp file: /xava/module.jsp
The type java.lang.CharSequence cannot be resolved. It is indirectly referenced from required .class files
29:                     || "xava.portlet.module".equals(name))
30:                 continue;
31:             String value = request.getParameter(name);
32:             result.append('&');
33:             result.append(name);
34:             result.append('=');
35:             result.append(value);


An error occurred at line: 165 in the jsp file: /xava/module.jsp
Arrays cannot be resolved
162:    <%
163:        File jsEditorsFolder = new File(realPath + "/xava/editors/js");     
164:        String[] jsEditors = jsEditorsFolder.list();
165:        Arrays.sort(jsEditors);
166:        for (int i = 0; i < jsEditors.length; i++) {
167:            if (jsEditors[i].endsWith(".js")) {
168:    %>


Stacktrace:
    org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:92)
    org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:330)
    org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:439)
    org.apache.jasper.compiler.Compiler.compile(Compiler.java:334)
    org.apache.jasper.compiler.Compiler.compile(Compiler.java:312)
    org.apache.jasper.compiler.Compiler.compile(Compiler.java:299)
    org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:586)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:317)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
    org.openxava.web.servlets.ModuleServlet.doGet(ModuleServlet.java:24)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.20 logs.
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1 回答 1

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问题是persistence.xml 中有多个持久性单元，同一个文件中还有一个格式错误。当我纠正它们时，我不再遇到同样的错误。

:)

费尔达

于 2014-06-02T07:32:31.733 回答