$sql = "INSERT INTO images (path, useremail, approved, flagged,caption,date) VALUES ('$target','$email',0,0, '$caption','$b')";
$sql1 = "INSERT INTO users (name, email, phone) VALUES ('$peoplename','$email','$phone')"
$conn->execute($sql, $sql1);
以上是我用来尝试写入 2 个表的代码。在我通过 COM 对象引入连接之前,我可以做到这一点不是问题,但现在我由于某种原因不能做到这一点。任何帮助,将不胜感激。