我有一个mysql查询如下：
SELECT questionid, question_number, question, actual_score, total_score,
ROUND(((actual_score / total_score) * 100), 2) AS satisfaction FROM
(
SELECT seq.`questionid`, seq.`question_number`, seql.`question`,
SUM(sea.`score`) AS actual_score,
SUM(seq.`max_score`) AS total_score
-- round(((sea.`score` / seq.`max_score`) * 100), 2) as satisfaction
FROM `survey_event_questions` seq
INNER JOIN `survey_event_question_langs` seql ON seq.`questionid` = seql.`questionid` AND seql.`langid` = '1'
INNER JOIN `survey_event_answers` sea ON seq.`questionid` = sea.`questionid`
INNER JOIN `survey_events` se ON sea.`eventid` = se.`eventid`
WHERE seq.`event_typeid` = '1' AND seq.`max_score` > 0 AND se.`survey_date` BETWEEN
'2014-01-02 13:00:00' AND '2014-05-02 14:59:59' AND se.`event_status` = 'Closed'
GROUP BY seq.`questionid`
) AS tbl;
此查询汇总 sea.score 和 seq.max_score 的列值并正确计算满意度值。
我想在不使用嵌套查询的情况下做到这一点。我正在使用的单个查询如下所示。
SELECT seq.`questionid`, seq.`question_number`, seql.`question`,
SUM(sea.`score`) AS actual_score,
SUM(seq.`max_score`) AS total_score,
round(((sea.`score` / seq.`max_score`) * 100), 2) as satisfaction
FROM `survey_event_questions` seq
INNER JOIN `survey_event_question_langs` seql ON seq.`questionid` = seql.`questionid` AND seql.`langid` = '1'
INNER JOIN `survey_event_answers` sea ON seq.`questionid` = sea.`questionid`
INNER JOIN `survey_events` se ON sea.`eventid` = se.`eventid`
WHERE seq.`event_typeid` = '1' AND seq.`max_score` > 0 AND se.`survey_date` BETWEEN
'2014-01-02 13:00:00' AND '2014-05-02 14:59:59' AND se.`event_status` = 'Closed'
GROUP BY seq.`questionid`
当我运行此查询时，它给了我对满意度列的错误计算，但在我使用嵌套查询时工作正常。