mysql - 如何在不使用限制函数的情况下计算 MySQL 子查询中重复次数最多的值

Question

我想计算表中重复次数最多的值，但它是在子查询中完成的，我的 SQLyog 不支持这种类型的查询，下面是我的查询：

SELECT `band`.`band_id`,`member_id`,`member_name`,`contact_no`  
FROM seasons 
INNER JOIN programs_recorded ON  programs_recorded.season_id=seasons.season_id 
INNER JOIN programs ON programs_recorded.program_id=programs.program_id 
INNER JOIN songs_performed ON songs_performed.program_id=programs.program_id 
INNER JOIN songs ON songs.song_id=songs_performed.song_id 
INNER JOIN `band` ON `band`.`song_id`=`songs`.`song_id` 
INNER JOIN `band_member` ON `band_member`.`band_id`=`band`.`band_id` 
WHERE `band`.`song_id` = ANY ( SELECT `songs_performed`.`song_id` 
                               FROM `songs_performed` 
                               GROUP BY `song_id` 
                               HAVING COUNT(`s_id`)>3)
GROUP BY `member_id` ; 

正如你在上面看到的，我写COUNT(s_id)>3的不是通用的，一个解决方案是我使用 GROUP BY 函数以及 order by 和 limit，但是 SQLyog 给出错误说它在这个版本中不受支持。

Answer 1

无论如何，这样的事情有什么问题......

SELECT DISTINCT b.band_id
              , member_id
              , member_name
              , contact_no  
           FROM seasons ss
           JOIN programs_recorded pr
             ON pr.season_id = ss.season_id 
           JOIN programs p
             ON pr.program_id = p.program_id 
           JOIN songs_performed sp
             ON sp.program_id = p.program_id 
           JOIN songs s
             ON s.song_id = sp.song_id 
           JOIN band b
             ON b.song_id = s.song_id 
           JOIN band_member bm
             ON bm.band_id = b.band_id 
           JOIN 
              ( SELECT sp.song_id 
                  FROM songs_performed sp
                 GROUP 
                    BY song_id 
                HAVING COUNT(s_id) > 3
              ) x
             ON x.song_id = b.song_id; 

??