2

这让我感到沮丧。我只是想创建一个共享内存缓冲区类,该类在通过 Boost.Interprocess 创建的共享内存中使用,我可以在其中读取/存储数据。我写了以下内容来测试功能

#include <boost/interprocess/shared_memory_object.hpp>
#include <boost/interprocess/mapped_region.hpp>
#include <iostream>
using namespace std;
using namespace boost::interprocess;

int main( int argc, char* argv[] ) {
    shared_memory_object::remove( "MyName" );
    // Create a shared memory object
    shared_memory_object shm ( create_only, "MyName", read_write );
    // Set size for the shared memory region
    shm.truncate(1000);
    // Map the whole shared memory in this process
    mapped_region region(shm, read_write);
    // Get pointer to the beginning of the mapped shared memory region
    int* start_ptr;
    start_ptr = static_cast<int*>(region.get_address());

    // Write data into the buffer
    int* write_ptr = start_ptr;
    for( int i= 0; i<10; i++ ) {
        cout << "Write data: " << i << endl;
        memcpy( write_ptr, &i, sizeof(int) );
        write_ptr++;
    }

    // Read data from the buffer
    int* read_ptr = start_ptr;
    int* data;
    for( int i= 0; i<10; i++ ) {
        memcpy( data, read_ptr, sizeof(int) );
        cout << "Read data: " << *data << endl;
        read_ptr++;
    }

    shared_memory_object::remove( "MyName" );
    return 0;
}

当我运行它时,它写入数据正常,但memcpy在读取循环中的第一个出现段错误。gdb 说:

程序收到信号 EXC_BAD_ACCESS,无法访问内存。原因:KERN_INVALID_ADDRESS 在地址:0x0000000000000000 0x00007fffffe007c5 in __memcpy()

(gdb) 在哪里

#0 0x00007fffffe007c5 in __memcpy () #1 0x0000000100000e45 in main (argc=1, argv=0x7fff5fbff9d0) at try.cpp:36

功能如此简单,我不知道我错过了什么。任何帮助都感激不尽。

4

2 回答 2

6

data没有被设置为指向任何东西。(确保在编译程序时启用了所有警告。)看起来它不应该是一个指针。

第二个循环应该是:

int* read_ptr = start_ptr;
int data;
for( int i= 0; i<10; i++ ) {
    memcpy( &data, read_ptr, sizeof(int) );
    cout << "Read data: " << data << endl;
    read_ptr++;
}
于 2010-03-03T18:20:12.710 回答
0

我不能在这里测试它,因为我没有boost可用的,但我有猜测。在这个例子中,shared_memory_object对象首先被用来写一个标志create_only

shared_memory_object shm (create_only, "MySharedMemory", read_write);

然后shared_memory_object用带有标志的第二个对象读取它open_only

shared_memory_object shm (open_only, "MySharedMemory", read_only);

看来您必须将您的标志更改shared_memory_object为适当的标志。

于 2010-03-03T18:26:54.683 回答