我试图让我的循环一遍又一遍，直到用户输入“退出”然后它就会退出。
基本上我试图让我的芬奇机器人根据它的定位方式改变鼻子的颜色，但我对如何让它允许用户在它已经定位后再次定位它感到困惑，这样鼻子的颜色就可以多次改变颜色。当它第一次运行时，Finch 将执行代码，但之后立即退出。
这是我的代码：
public class finch {
public static final int INCREASE = 20;
public static final int SEC = 1000;
public static final int MAXSPEED = 255;
public static final int HALFSEC = 500;
public static Finch myFinch;
public static void main(String[] args) {
myFinch = new Finch();
Menu();
}
public static void Menu() {
Scanner console = new Scanner(System.in);
System.out.println("Enter your choice:" + "");
int input;
int input1;
boolean flag=true;
while(flag){
System.out.println("1.\t" + "Rolling" + "Finch");
System.out.println("2.\t" + "Obedient" + "Finch");
System.out.println("3.\t" + "Exit");
System.out.println();
System.out.println("Enter your choice:");
System.out.println();
input = console.nextInt();
flag=false;
if (input == 1) {
//input = DarkFinch;
System.out.println("Position the Finch \"down\" or \"up\" to change nose color");
rolling(myFinch);
} else if (input == 2) {
// input = ChasetheFinch;
// System.out.println("Chase The Finch");
} else if (input == 3) {
// input = Exit;
System.out.println("Goodbye");
} else {
// System.out.println("Try again");
flag=true;
/* return Menu(); */
}
}
}
public static boolean rolling(Finch myFinch) {//This method will change the Finches nose color depending on the Finches position.
//"up" = place the finch upright standing on its tail
for (int i = 1; i <= 20; i++) {
while (myFinch.isBeakDown() || myFinch.isBeakUp()) {
if (myFinch.isBeakDown()) {
myFinch.setLED(0,0,255,3000);
} else if (myFinch.isBeakUp()) {
myFinch.setLED(255,0,0,3000);
} else {
myFinch.setLED(0,0,0,5000);
}
}
}
return true;
}
}