0

我有一个工厂，它返回一个具有多个属性的对象。但是每个属性值都是通过 ajax 调用计算的，在某些情况下，我会承诺链接以设置属性值。在我返回对象之前，我如何确保所有 ajax 调用都已完成，以便分配属性值

我的工厂看起来像这样

app.factory('Resource', ['$http', '$q', function ($http, $q) {
    var Resource = {
    masterDB: null,
    replicaDB: null,
    replicaCluster: null,
    masterForests: null,
    forestHosts:{}
};

    Resource.setMasterDB = function (dbname) {
        console.log('inside setMasterDB', dbname);
        this.masterDB = dbname;
    };


    Resource.getResources = function (dbname) {
        var  url = '/manage/v2/databases/'+ dbname + '?format=json';
        $http.get(url).then(function (response) {
            Resource.masterForests = getAttachedForests(response.data);
            console.warn('Master Forests = ', Resource.masterForests);
            return response;
        }).then(function (response) {
            Resource.replicaCluster = getReplicaClusters(response.data);
            console.warn('Replica Cluster = ',Resource.replicaCluster);
        }).then(function () {
            console.log('final then',  Resource.masterForests);
            var reqs = function () {
                var arr = [];
                angular.forEach(Resource.masterForests, function(forestName){
                    arr.push($http.get('/manage/v2/forests/'+ forestName + '?format=json'));
                });
                return arr;
            }.call();

                console.log('reqs = ', reqs);

            $q.all(reqs).then(function (results) {
                console.warn(results);
                angular.forEach(results, function(result){
                    console.log('HOST', getForestHost(result.data));
                });
                return results;
            });
        });

    };
    console.warn('RESOURCES: ', JSON.stringify(Resource));
    return Resource;

}]);
4

2 回答 2

1

我们遇到了必须从两个不同的 ajax 响应更新数据的情况，我们遵循以下方法。

例如：

function functionname()
{

var First_Response = $http.$get("/test1/test2/...");
var Second_Response = $http.$get("test3/test4/...");
return $q.all([First_Response,Second_Response]); // This function will return only when all the ajax responses are obtained.
}

在以下网址中： https ://docs.angularjs.org/api/ng/service/ $q

提到 $q.all 只有当数组中提到的所有请求都得到 ajax 响应时才会返回结果。我们尝试了这种方法，它对我们有用。希望能给一些指点

于 2014-05-15T11:46:57.923 回答
0

这是工作代码 

 getResources: function (dbname) {
            var  url = '/manage/v2/databases/'+ dbname + '?format=json';
            return $http.get(url).then(function (response) {
                Resource.masterForests = getAttachedForests(response.data);
                Resource.appservers = getAttachedAppServers(response.data);
                Resource.replicaClusters = getReplicaClusters(response.data);
                console.warn('Master Forests = ', Resource.masterForests);
                return Resource.replicaClusters;
            }).then(function(replicaClusters) {
                var clusterArr = [];
                angular.forEach(replicaClusters, function(cluster) {
                    clusterArr.push($http.get('/manage/v2/clusters/'+ cluster + '?format=json'));
                });
                return $q.all(clusterArr).then(function(results) {
                    angular.forEach(results, function(result) {
                        var cluster = result.data['foreign-cluster-default'].name;
                        var dbs = getReplicaDBs(result.data);
                        Resource.replicaDBs[cluster] = dbs; 
                    });
                });
            }).then(function() {
                var forestarr = [];
                    angular.forEach(Resource.masterForests, function(forestName){
                        forestarr.push($http.get('/manage/v2/forests/'+ forestName + '?format=json'));
                    });     
                return $q.all(forestarr).then(function (results) {
                    angular.forEach(results, function(result){
                        var host = getForestHost(result.data);
                        var forest = result.data['forest-default'].name;
                        Resource.forestHosts.push(host);
                        // group forest by hosts
                        groupForestsByHost(Resource, host, forest); 
                    });
                });
            });
        }

在控制器中

Resource.getResources($scope.db).then(function() {
     $scope.masterForests = Resource.masterForests;
     $scope.replicaClusters = Resource.replicaClusters;
     $scope.forestHosts = Resource.forestHosts;
     $scope.forestsOnHosts = Resource.forestsOnHosts;
     $scope.replicaDBs = Resource.replicaDBs;
     $scope.appservers = Resource.appservers;
 }
于 2014-05-17T08:12:39.270 回答