16

我有以下 XML 架构:

<Courses semester="1">
    <Course code="A231" credits="3">Intermediate A</Course>
    <Course code="A105" credits="2">Intro to A</Course>
    <Course code="B358" credits="4">Advanced B</Course>
</Courses>

我需要将其转换为 POJO:

public class Schedule
{
   public int semester;
   public Course[] courses;
}

public class Course
{
   public String code;
   public int credits;
   public String name;
}

这里有两件重要的事情需要注意:

  1. 课程对象未包含在标签中
  2. 一些属性是属性

我如何需要注释我的对象才能让 FasterXML 反序列化这个 xml?

4

1 回答 1

22

您必须向项目添加jackson-dataformat-xml依赖项:

<dependency>
    <groupId>com.fasterxml.jackson.dataformat</groupId>
    <artifactId>jackson-dataformat-xml</artifactId>
    <version>2.3.3</version>
</dependency>

之后,您可以通过这种方式使用 XML 注释:

@JacksonXmlRootElement(localName = "Courses")
class Schedule {

    @JacksonXmlProperty(isAttribute = true)
    private int semester;

    @JacksonXmlProperty(localName = "Course")
    private Course[] courses;

    // getters, setters, toString, etc
}

class Course {

    @JacksonXmlProperty(isAttribute = true)
    private String code;

    @JacksonXmlProperty(isAttribute = true)
    private int credits;

    @JacksonXmlText(value = true)
    private String name;

    // getters, setters, toString, etc
}

现在,您必须使用XmlMapper而不是ObjectMapper

JacksonXmlModule module = new JacksonXmlModule();
module.setDefaultUseWrapper(false);
XmlMapper xmlMapper = new XmlMapper(module);

System.out.println(xmlMapper.readValue(xml, Schedule.class));

上面的脚本打印:

Schedule [semester=1, courses=[[code=A231, credits=3, name=Intermediate A], [code=A105, credits=2, name=Intro to A], [code=B358, credits=4, name=Advanced B]]]
于 2014-05-13T20:12:14.347 回答