我正在 WPF 中做一个应用程序,并且我正在使用 DesignData 来加快 UI 创建过程,因为启动应用程序是一个缓慢的过程。
我找不到用设计数据设置组合框的 SelectedItem 的方法。检查以下示例:
XAML:
<Window x:Class="DesignDataTest.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DataContext="{d:DesignData Source=SampleData.xaml}" >
<ComboBox ItemsSource="{Binding GroupingViewModel.Items}" SelectedItem="{Binding GroupingViewModel.SelectedItem}" DisplayMemberPath="Description" Width="100" Height="30" />
</Window>
视图模型:
public class MainViewModel
{
public GroupingViewModel GroupingViewModel { get; private set; }
public MainViewModel()
{
this.GroupingViewModel = new GroupingViewModel();
}
}
public class GroupingViewModel
{
public List<GroupingViewModel> Items { get; private set; }
public GroupingViewModel SelectedItem { get; set; }
public string Description { get; set; }
public GroupingViewModel()
{
this.Items = new List<GroupingViewModel>();
}
}
和设计数据:
<designDataTest:MainViewModel.GroupingViewModel>
<designDataTest:GroupingViewModel Description="1">
<designDataTest:GroupingViewModel.Items>
<designDataTest:GroupingViewModel Description="1" />
<designDataTest:GroupingViewModel Description="2" />
<designDataTest:GroupingViewModel Description="3" />
</designDataTest:GroupingViewModel.Items>
<designDataTest:GroupingViewModel.SelectedItem>
<designDataTest:GroupingViewModel Description="1" />
</designDataTest:GroupingViewModel.SelectedItem>
</designDataTest:GroupingViewModel>
</designDataTest:MainViewModel.GroupingViewModel>
</designDataTest:MainViewModel>
似乎组合框期望从可用项目集合中接收一个元素,但我不知道如何从设计数据文件中引用这些元素之一。
有什么提示吗?