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我修改了一个 C# 插件，它是 Visual Studio 2.0 的 Python 工具的一部分，并希望在代码中查看 Debug.WriteLine 和 Trace.WriteLine 语句的输出。请注意，该插件用于 Visual Studio 2013 本身，修改 python 进程的调试....

我希望我可以按照 pminaev在此处的 PTVS 讨论论坛上的devenv.exe.config建议添加一个跟踪侦听器（将另一个 VS 附加到 VS 本身似乎很笨拙，所以我希望避免这种情况）。

我认为其他 .NET 应用程序的正确配置似乎不适用于 VS2013 本身。 我的努力记录在下面。

如果有人设法将插件调试/跟踪输出重定向到 Visual Studio 控制台（或比另一个附加的 VS 实例更方便的任何其他地方），非常感谢提示......

我的 Google-fu 出现了几个示例，基于这些示例我尝试添加...

<system.diagnostics>
    <trace autoflush="true" />
        <listeners>
            <add name="myConsoleTraceListener" type="System.Diagnostics.ConsoleTraceListener" />
        </listeners>
    </trace>
</system.diagnostics>

...和...

<system.diagnostics>
    <source name="System.ServiceModel.MessageLogging" switchValue="Verbose, ActivityTracing">
        <listeners>
            <add name="myTraceListener" />
        </listeners>
    </source>
    <sharedListeners>
        <add name="myTraceListener" type="System.Diagnostics.ConsoleTraceListener" />
    </sharedListeners>
</system.diagnostics>

之后启动 PTVS，没有什么可用的。无论使用哪种配置，我都会弹出一个窗口：

The `Python Tools Package' package id not load correctly.

The problem may have been caused by a configuration change or by
the installation of another extension.  You can get more information by
examining the file
'C:\Users\XXX\AppData\Roaming\Microsoft\VisualStudio\12.0\Acti
vityLog.xml'.

ActivityLog 对我来说意义不大：

<entry>
    <record>41</record>
    <time>2014/05/12 07:52:47.851</time>
    <type>Error</type>
    <source>VisualStudio</source>
    <description>CreateInstance failed for package [Python Tools Package]</description>
    <guid>{6DBD7C1E-1F1B-496D-AC7C-C55DAE66C783}</guid>
    <hr>80131604</hr>
    <errorinfo>Exception has been thrown by the target of an invocation.</errorinfo>
</entry>
<entry>
    <record>42</record>
    <time>2014/05/12 07:52:47.851</time>
    <type>Error</type>
    <source>VisualStudio</source>
    <description>End package load [Python Tools Package]</description>
    <guid>{6DBD7C1E-1F1B-496D-AC7C-C55DAE66C783}</guid>
    <hr>80004005 - E_FAIL</hr>
    <errorinfo>Exception has been thrown by the target of an invocation.</errorinfo>
</entry>

当我尝试附加到远程 python 进程时，我得到另一个弹出窗口：

Unable to connect to 'secret@server'.  Operation not supported.
Unknown error: 0x80131902.

Google-foo 建议这是加载 .NET 版本的一些失败......？

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1 回答 1

1

我想为我写的插件做类似的事情：pMixins。我使用 log4net 而不是 System.Diagnostics，但想将日志消息路由到 Visual Studio 输出窗口。

我从来没有使用基于配置的方法来工作，最终以编程方式进行布线。此外，我必须创建一个自定义日志编写器来写入 Visual Studio 输出窗口。

在我的包文件（https://github.com/ppittle/pMixins/blob/master/pMixins.VSPackage/pMixinsVisualStudioCodeGenerateInitializer.cs）中：

protected override void Initialize()
{

      //Create a Visual Studio Writer
       _visualStudioWriter = new VisualStudioWriter(dte, this);

      //Initialize Logging
      Log4NetInitializer.Initialize(_visualStudioWriter, this);
 }

VisualStudioWriter（摘要）（https://github.com/ppittle/pMixins/blob/master/pMixins.VSPackage/Infrastructure/VisualStudioWriter.cs）：

public class VisualStudioWriter : IVisualStudioWriter
{  
    private EnvDTE.OutputWindowPane _outputWindowPane;

    public VisualStudioWriter(DTE dte, System.IServiceProvider serviceProvider)
    {                      
        _outputWindowPane = LoadOutputWindowPane(dte);
    }

    private EnvDTE.OutputWindowPane LoadOutputWindowPane(DTE dte)
    {
        const string windowName = "pMixins Code Generator";
        EnvDTE.OutputWindowPane pane = null;
        EnvDTE.Window window = dte.Windows.Item(EnvDTE.Constants.vsWindowKindOutput);
        if (window != null)
        {
            EnvDTE.OutputWindow output = window.Object as EnvDTE.OutputWindow;
            if (output != null)
            {
                pane = output.ActivePane;
                if (pane == null || pane.Name != windowName)
                {
                    for (int ix = output.OutputWindowPanes.Count; ix > 0; ix--)
                    {
                        pane = output.OutputWindowPanes.Item(ix);
                        if (pane.Name == windowName)
                            break;
                    }
                    if (pane == null || pane.Name != windowName)
                        pane = output.OutputWindowPanes.Add(windowName);
                    if (pane != null)
                        pane.Activate();
                }
            }
        }
        return pane;
    }

    public void OutputString(string s)
    {
        _outputWindowPane.OutputString(s);
    }
 }

Log4NetInitializer（总结）https://github.com/ppittle/pMixins/blob/master/CopacciSoftware.CodeGenerator.StarterKit/Logging/Log4NetInitializer.cs

public static class Log4NetInitializer
{
    public static void Initialize(IVisualStudioWriter visualStudioWriter,
                       IServiceProvider serviceProvider)
    {
       //http://stackoverflow.com/questions/650694/changing-the-log-level-programmaticaly-in-log4net
       var outputWindowAppender =
           new VisualStudioOutputWindowAppender(visualStudioWriter)
           {
               Layout =
                       new PatternLayout(@"%date{HH:mm:ss,fff} %thread% %-5level [%logger{2}] %message%newline"),
                    Threshold =
                    #if DEBUG
                     Level.Debug
                     #else
                    Level.Info
                        #endif
           };


       log4net.Config.BasicConfigurator.Configure(
                outputWindowAppender);                

    }
}

最后，VisualStudioOutputWindowAppender ( https://github.com/ppittle/pMixins/blob/master/CopacciSoftware.CodeGenerator.StarterKit/Logging/VisualStudioOutputWindowAppender.cs )

public class VisualStudioOutputWindowAppender : AppenderSkeleton
{
    public IVisualStudioWriter OutputWindow { get; set; }

    public VisualStudioOutputWindowAppender(IVisualStudioWriter outputWindow)
    {
        OutputWindow = outputWindow;

        Layout = new PatternLayout("%-5level %logger - %message%newline");
    }

    protected override void Append(LoggingEvent loggingEvent)
    {
        if (null == OutputWindow)
            return;

        if (null == loggingEvent)
            return;

        OutputWindow.OutputString(RenderLoggingEvent(loggingEvent));
    }
}

希望有帮助

于 2014-06-26T10:37:12.550 回答