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我有一个查询三个临时表。

  1. 表一 当 PC = 6 而不是 7 时返回 PID
  2. 表二 当 PC = 1 而不是 7 时返回 PID
  3. 表三 返回 PID 而不是 7

前两个临时表有一个完美的内连接，只返回 PC = 6 和 PC = 1 的 PID，但不等于 7。

但是，我想要的是第三部分，在 PC 上右外连接，并返回所有包含 PC = 6 或 PC = 1 的 PID，而不是在内连接中。相反，右外连接返回相同的值。有人可以帮帮我吗？

 --CREATE TEMP TABLE TO PULL PIDs w PLCs but no True Owner--
SELECT 
Distinct P.PropertyID as PID
,PC.LocationID AS PLC

INTO #TempPLC

FROM  
Property AS P
left join
PropertyContact As PC on PC.PropertyID = P.PropertyID


WHERE
    P.PropertyID=PC.PropertyID
    and 
    PC.ContactRoleID = 6 
    and not exists 
    (select 1 
    from 
    Enterprise.dbo.PropertyContact 
    where 
    PropertyID=P.PropertyID 
    and 
    ContactRoleID=7) 




--CREATE TEMP TABLE TO PULL PIDs w Recorded but no True Owner--
USE ENTERPRISE--    

SELECT 
Distinct P.PropertyID as PID
,PC.LocationID AS Recorded

INTO #TempRecorded
FROM 
Property AS P
left join
PropertyContact As PC on PC.PropertyID = P.PropertyID

WHERE
    P.PropertyID=PC.PropertyID
    and
    PC.ContactRoleID = 3 
    (select 1 
    from 
    Enterprise.dbo.PropertyContact 
    where 
    PropertyID=P.PropertyID 
    and 
    ContactRoleID=7) 


--CREATE TEMP TABLE TO PULL PIDs w PLCs but no True Owner--

SELECT 
P.PropertyID as PID
,PC.LocationID AS RemainingLocs


INTO #TempRemaining
FROM
Property AS P
left join
PropertyContact As PC on PC.PropertyID = P.PropertyID

WHERE
    P.PropertyID=PC.PropertyID
    and not exists 
    (select 1 
    from 
    Enterprise.dbo.PropertyContact 
    where 
    PropertyID=P.PropertyID 
    and 
    ContactRoleID=7)    

--RETURN RESULTS OF ALL PIDS w. BOTH RECORDED AND TRUE OWNERS--
SELECT

Distinct #TempRemaining.PID
,#TempRemaining.RemainingLocs
,#TempRecorded.Recorded

FROM
#TempPLC
inner join
#TempRecorded on #TempRecorded.PID = #TempPLC.PID
right join
#TempRemaining on #TempRecorded.Recorded = #TempRemaining.RemainingLocs


WHERE
#TempRecorded.Recorded = #TempPLC.PLC

--DROP TEMP TABLES--
drop table #TempPLC
drop table #TempRecorded
drop table #TempRemaining
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