将两个数组与您想要的字段(列)进行比较,然后只返回那些条目(感谢键):
$col = 'NAME';
$diff = array_intersect_key($b, array_diff(array_column($b, $col), array_column($a, $col)));
print_r($diff);
如果您更喜欢这种不那么二次但线性的,您也可以通过迭代来解决它(受georg's answer的启发但array_column()
再次使用):
$filtered = function ($col, $a, $b) {
return iterator_to_array(call_user_func(function () use ($col, $a, $b) {
$coled = array_flip(array_column($a, $col));
foreach ($b as $bk => $bv) if (!isset($coled[$bv[$col]])) yield $bk => $bv;
}));
};
print_r($filtered('NAME', $a, $b));
使用$a
和$b
概述,您将获得两个示例的以下结果:
Array
(
[0] => Array
(
[ID] => 543547564
[NAME] => Name_1
[PREVIEW_TEXT] => Text_1
)
[2] => Array
(
[ID] => 333876833
[NAME] => Name_3
[PREVIEW_TEXT] => Text_3
)
)
// 1.) - diff against column, intersect keys
$filtered = function($col, $a, $b) {
return array_intersect_key($b, array_diff(array_column($b, $col), array_column($a, $col)));
};
// 2.) - iterate and take only unset by column
$filtered = function ($col, $a, $b) {
return iterator_to_array(call_user_func(function () use ($col, $a, $b) {
$coled = array_flip(array_column($a, $col));
foreach ($b as $bk => $bv) if (!isset($coled[$bv[$col]])) yield $bk => $bv;
}));
};
// 3.) - array_udiff against column
$filtered = function($col, $a, $b) {
return array_udiff($b, $a, function ($a, $b) use ($col) {
return strcmp($a[$col], $b[$col]);
});
};
用法:
print_r($filtered('NAME', $a, $b));
$a
包含要从数组中删除的元素的数组在哪里$b
。$a
问题的第一个数组和问题$b
的第二个数组也是如此。