103

我阅读了一些将 jsons 发布到服务器的示例。

有人说：

OkHttp 是 Java 提供的 HttpUrlConnection 接口的实现。它为编写内容提供输入流，并且不知道（或关心）内容是什么格式。

现在我想用名称和密码的参数向 URL 发布一个正常的帖子。

这意味着我需要自己将名称和值对编码到流中吗？

4

14 回答 14

125

根据文档，OkHttp 版本 3 替换FormEncodingBuilder为FormBodyand FormBody.Builder()，因此旧示例不再适用。

现在对窗体和多部分实体进行了建模。我们 FormEncodingBuilder用更强大的FormBody组合 FormBody.Builder取代了不透明。

同样，我们已经升级MultipartBuilder到 MultipartBody、MultipartBody.Part和MultipartBody.Builder。

因此，如果您使用的是 OkHttp 3.x，请尝试以下示例：

OkHttpClient client = new OkHttpClient();

RequestBody formBody = new FormBody.Builder()
        .add("message", "Your message")
        .build();
Request request = new Request.Builder()
        .url("https://www.example.com/index.php")
        .post(formBody)
        .build();

try {
    Response response = client.newCall(request).execute();

    // Do something with the response.
} catch (IOException e) {
    e.printStackTrace();
}
于 2016-02-01T16:54:51.257 回答
110

当前接受的答案已过时。现在，如果您想创建一个发布请求并向其添加参数，您应该使用 MultipartBody.Builder，因为Mime Craft now is deprecated。

RequestBody requestBody = new MultipartBody.Builder()
        .setType(MultipartBody.FORM)
        .addFormDataPart("somParam", "someValue")
        .build();

Request request = new Request.Builder()
        .url(BASE_URL + route)
        .post(requestBody)
        .build();
于 2016-10-16T14:08:41.583 回答
38 
private final OkHttpClient client = new OkHttpClient();

  public void run() throws Exception {
    RequestBody formBody = new FormEncodingBuilder()
        .add("search", "Jurassic Park")
        .build();
    Request request = new Request.Builder()
        .url("https://en.wikipedia.org/w/index.php")
        .post(formBody)
        .build();

    Response response = client.newCall(request).execute();
    if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);

    System.out.println(response.body().string());
  }
于 2015-04-22T11:02:55.227 回答
19

您需要通过使用URLEncoder"="转义字符串并使用and连接它们来自己对其进行编码"&"。或者您可以使用Mimecraft的FormEncoder，它为您提供了一个方便的构建器。

FormEncoding fe = new FormEncoding.Builder()
    .add("name", "Lorem Ipsum")
    .add("occupation", "Filler Text")
    .build();
于 2014-05-04T13:39:24.347 回答
17

你可以这样：

    MediaType JSON = MediaType.parse("application/json; charset=utf-8");
    RequestBody body = RequestBody.create(JSON, "{"jsonExample":"value"}");

    OkHttpClient client = new OkHttpClient();

    Request request = new Request.Builder()
            .url(url)
            .post(body)
            .addHeader("Authorization", "header value") //Notice this request has header if you don't need to send a header just erase this part
            .build();

    Call call = client.newCall(request);

    call.enqueue(new Callback() {
        @Override
        public void onFailure(Request request, IOException e) {

            Log.e("HttpService", "onFailure() Request was: " + request);

            e.printStackTrace();
        }

        @Override
        public void onResponse(Response r) throws IOException {

            response = r.body().string();

            Log.e("response ", "onResponse(): " + response );

        }
    });
于 2015-12-24T17:18:29.587 回答
6

POST标头中带有令牌的OkHttp请求

       RequestBody requestBody = new MultipartBody.Builder()
            .setType(MultipartBody.FORM)
            .addFormDataPart("search", "a")
            .addFormDataPart("model", "1")
            .addFormDataPart("in", "1")
            .addFormDataPart("id", "1")
            .build();
    OkHttpClient client = new OkHttpClient();
    okhttp3.Request request = new okhttp3.Request.Builder()
            .url("https://somedomain.com/api")
            .post(requestBody)
            .addHeader("token", "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJpc3MiOiIkMnkkMTAkZzZrLkwySlFCZlBmN1RTb3g3bmNpTzltcVwvemRVN2JtVC42SXN0SFZtbzZHNlFNSkZRWWRlIiwic3ViIjo0NSwiaWF0IjoxNTUwODk4NDc0LCJleHAiOjE1NTM0OTA0NzR9.tefIaPzefLftE7q0yKI8O87XXATwowEUk_XkAOOQzfw")
            .addHeader("cache-control", "no-cache")
            .addHeader("Postman-Token", "7e231ef9-5236-40d1-a28f-e5986f936877")
            .build();

    client.newCall(request).enqueue(new Callback() {
        @Override
        public void onFailure(Call call, IOException e) {
            e.printStackTrace();
        }

        @Override
        public void onResponse(Call call, okhttp3.Response response) throws IOException {
            if (response.isSuccessful()) {
                final String myResponse = response.body().string();

                MainActivity.this.runOnUiThread(new Runnable() {
                    @Override
                    public void run() {
                        Log.d("response", myResponse);
                        progress.hide();
                    }
                });
            }
        }
    });
于 2019-02-23T05:24:03.613 回答
4

要将 okhttp 添加为依赖项，请执行以下操作

  • 右键单击android studio上的应用程序打开“模块设置”
  • “依赖”->“添加库依赖”->“com.squareup.okhttp3:okhttp:3.10.0”->添加->确定..

现在你有 okhttp 作为依赖

现在设计一个如下所示的接口，这样我们就可以在收到网络响应后回调我们的活动。

public interface NetworkCallback {

    public void getResponse(String res);
}

我创建了一个名为 NetworkTask 的类，所以我可以使用这个类来处理所有的网络请求

    public class NetworkTask extends AsyncTask<String , String, String>{

    public NetworkCallback instance;
    public String url ;
    public String json;
    public int task ;
    OkHttpClient client = new OkHttpClient();
    public static final MediaType JSON
            = MediaType.parse("application/json; charset=utf-8");

    public NetworkTask(){

    }

    public NetworkTask(NetworkCallback ins, String url, String json, int task){
        this.instance = ins;
        this.url = url;
        this.json = json;
        this.task = task;
    }


    public String doGetRequest() throws IOException {
        Request request = new Request.Builder()
                .url(url)
                .build();

        Response response = client.newCall(request).execute();
        return response.body().string();
    }

    public String doPostRequest() throws IOException {
        RequestBody body = RequestBody.create(JSON, json);
        Request request = new Request.Builder()
                .url(url)
                .post(body)
                .build();
        Response response = client.newCall(request).execute();
        return response.body().string();
    }

    @Override
    protected String doInBackground(String[] params) {
        try {
            String response = "";
            switch(task){
                case 1 :
                    response = doGetRequest();
                    break;
                case 2:
                    response = doPostRequest();
                    break;

            }
            return response;
        }catch (Exception e){
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String s) {
        super.onPostExecute(s);
        instance.getResponse(s);
    }
}

现在让我展示如何获取活动的回调

    public class MainActivity extends AppCompatActivity implements NetworkCallback{
    String postUrl = "http://your-post-url-goes-here";
    String getUrl = "http://your-get-url-goes-here";
    Button doGetRq;
    Button doPostRq;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Button button = findViewById(R.id.button);

        doGetRq = findViewById(R.id.button2);
    doPostRq = findViewById(R.id.button1);

        doPostRq.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                MainActivity.this.sendPostRq();
            }
        });

        doGetRq.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                MainActivity.this.sendGetRq();
            }
        });
    }

    public void sendPostRq(){
        JSONObject jo = new JSONObject();
        try {
            jo.put("email", "yourmail");
            jo.put("password","password");

        } catch (JSONException e) {
            e.printStackTrace();
        }
    // 2 because post rq is for the case 2
        NetworkTask t = new NetworkTask(this, postUrl,  jo.toString(), 2);
        t.execute(postUrl);
    }

    public void sendGetRq(){

    // 1 because get rq is for the case 1
        NetworkTask t = new NetworkTask(this, getUrl,  jo.toString(), 1);
        t.execute(getUrl);
    }

    @Override
    public void getResponse(String res) {
    // here is the response from NetworkTask class
    System.out.println(res)
    }
}
于 2018-05-25T05:32:07.537 回答
3

这是在没有请求正文的情况下实现 OKHTTP 发布请求的可能解决方案之一。

RequestBody reqbody = RequestBody.create(null, new byte[0]);  
Request.Builder formBody = new Request.Builder().url(url).method("POST",reqbody).header("Content-Length", "0");
clientOk.newCall(formBody.build()).enqueue(OkHttpCallBack());
于 2016-01-18T19:17:32.633 回答
2

您应该查看lynda.com上的教程。这是一个如何对参数进行编码、发出 HTTP 请求然后将响应解析为 json 对象的示例。

public JSONObject getJSONFromUrl(String str_url, List<NameValuePair> params) {      
        String reply_str = null;
        BufferedReader reader = null;

        try {
            URL url = new URL(str_url);
            OkHttpClient client = new OkHttpClient();
            HttpURLConnection con = client.open(url);                           
            con.setDoOutput(true);
            OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream());
            writer.write(getEncodedParams(params));
            writer.flush();     
            StringBuilder sb = new StringBuilder();
            reader = new BufferedReader(new InputStreamReader(con.getInputStream()));           
            String line;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }           
            reply_str = sb.toString();              
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        } finally {
            if (reader != null) {
                try {
                    reader.close();
                } catch (IOException e) {
                    e.printStackTrace();
                    return null;
                }
            }
        }

        // try parse the string to a JSON object. There are better ways to parse data.
        try {
            jObj = new JSONObject(reply_str);            
        } catch (JSONException e) {   
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }     
      return jObj;
    }

    //in this case it's NameValuePair, but you can use any container
    public String getEncodedParams(List<NameValuePair> params) {
        StringBuilder sb = new StringBuilder();
        for (NameValuePair nvp : params) {
            String key = nvp.getName();
            String param_value = nvp.getValue();
            String value = null;
            try {
                value = URLEncoder.encode(param_value, "UTF-8");
            } catch (UnsupportedEncodingException e) {
                e.printStackTrace();
            }

            if (sb.length() > 0) {
                sb.append("&");
            }
            sb.append(key + "=" + value);
        }
        return sb.toString();
    }
于 2014-08-22T04:31:35.730 回答
2 
   protected Void doInBackground(String... movieIds) {
                for (; count <= 1; count++) {
                    try {
                        Thread.sleep(1000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }

                Resources res = getResources();
                String web_link = res.getString(R.string.website);

                OkHttpClient client = new OkHttpClient();

                RequestBody formBody = new FormBody.Builder()
                        .add("name", name)
                        .add("bsname", bsname)
                        .add("email", email)
                        .add("phone", phone)
                        .add("whatsapp", wapp)
                        .add("location", location)
                        .add("country", country)
                        .add("state", state)
                        .add("city", city)
                        .add("zip", zip)
                        .add("fb", fb)
                        .add("tw", tw)
                        .add("in", in)
                        .add("age", age)
                        .add("gender", gender)
                        .add("image", encodeimg)
                        .add("uid", user_id)
                        .build();
                Request request = new Request.Builder()
                        .url(web_link+"edit_profile.php")
                        .post(formBody)
                        .build();

                try {
                    Response response = client.newCall(request).execute();

                    JSONArray array = new JSONArray(response.body().string());
                    JSONObject object = array.getJSONObject(0);

                    hashMap.put("msg",object.getString("msgtype"));
                    hashMap.put("msg",object.getString("msg"));
                    // Do something with the response.
                } catch (IOException e) {
                    e.printStackTrace();
                } catch (JSONException e) {
                    e.printStackTrace();
                }



                return null;
            }
于 2017-06-14T08:30:09.753 回答
1

这是我在方法映射和数据中进行发布请求的方法，例如

HashMap<String, String> param = new HashMap<String, String>();

param.put("Name", name);
param.put("Email", email);
param.put("Password", password);
param.put("Img_Name", "");

final JSONObject result = doPostRequest(map,Url);

public static JSONObject doPostRequest(HashMap<String, String> data, String url) {

    try {
        RequestBody requestBody;
        MultipartBuilder mBuilder = new MultipartBuilder().type(MultipartBuilder.FORM);

        if (data != null) {


            for (String key : data.keySet()) {
                String value = data.get(key);
                Utility.printLog("Key Values", key + "-----------------" + value);

                mBuilder.addFormDataPart(key, value);

            }
        } else {
            mBuilder.addFormDataPart("temp", "temp");
        }
        requestBody = mBuilder.build();


        Request request = new Request.Builder()
                .url(url)
                .post(requestBody)
                .build();

        OkHttpClient client = new OkHttpClient();
        Response response = client.newCall(request).execute();
        String responseBody = response.body().string();
        Utility.printLog("URL", url);
        Utility.printLog("Response", responseBody);
        return new JSONObject(responseBody);

    } catch (UnknownHostException | UnsupportedEncodingException e) {

        JSONObject jsonObject=new JSONObject();

        try {
            jsonObject.put("status","false");
            jsonObject.put("message",e.getLocalizedMessage());
        } catch (JSONException e1) {
            e1.printStackTrace();
        }
        Log.e(TAG, "Error: " + e.getLocalizedMessage());
    } catch (Exception e) {
        e.printStackTrace();
        JSONObject jsonObject=new JSONObject();

        try {
            jsonObject.put("status","false");
            jsonObject.put("message",e.getLocalizedMessage());
        } catch (JSONException e1) {
            e1.printStackTrace();
        }
        Log.e(TAG, "Other Error: " + e.getLocalizedMessage());
    }
    return null;
}
于 2016-07-22T12:01:00.030 回答
1
  1. 将以下内容添加到 build.gradle

compile 'com.squareup.okhttp3:okhttp:3.7.0'

  1. 创建一个新线程，在新线程中添加以下代码。
OkHttpClient client = new OkHttpClient();
MediaType MIMEType= MediaType.parse("application/json; charset=utf-8");
RequestBody requestBody = RequestBody.create (MIMEType,"{}");
Request request = new Request.Builder().url(url).post(requestBody).build();
Response response = client.newCall(request).execute();
于 2017-11-10T03:02:19.463 回答
0

如果您想在 okhttp 中发布参数作为正文内容，可以使用 content-type 为“application/x-www-form-urlencoded”的加密字符串，您可以首先使用 URLEncoder 对数据进行编码，然后使用：

final MediaType MEDIA_TYPE_MARKDOWN = MediaType.parse("application/x-www-form-urlencoded");

okhttp3.Request request = new okhttp3.Request.Builder()
    .url(urlOfServer)
    .post(RequestBody.create(MEDIA_TYPE_MARKDOWN, yourBodyDataToPostOnserver))
    .build();

您可以根据需要添加标题。

于 2021-02-25T13:15:07.663 回答
-4 
 public static JSONObject doPostRequestWithSingleFile(String url,HashMap<String, String> data, File file,String fileParam) {

        try {
            final MediaType MEDIA_TYPE_PNG = MediaType.parse("image/png");

            RequestBody requestBody;
            MultipartBuilder mBuilder = new MultipartBuilder().type(MultipartBuilder.FORM);

            for (String key : data.keySet()) {
                String value = data.get(key);
                Utility.printLog("Key Values", key + "-----------------" + value);

                mBuilder.addFormDataPart(key, value);

            }
            if(file!=null) {
                Log.e("File Name", file.getName() + "===========");
                if (file.exists()) {
                    mBuilder.addFormDataPart(fileParam, file.getName(), RequestBody.create(MEDIA_TYPE_PNG, file));
                }
            }
            requestBody = mBuilder.build();
            Request request = new Request.Builder()
                    .url(url)
                    .post(requestBody)
                    .build();

            OkHttpClient client = new OkHttpClient();
            Response response = client.newCall(request).execute();
            String result=response.body().string();
            Utility.printLog("Response",result+"");
            return new JSONObject(result);

        } catch (UnknownHostException | UnsupportedEncodingException e) {
            Log.e(TAG, "Error: " + e.getLocalizedMessage());
            JSONObject jsonObject=new JSONObject();

            try {
                jsonObject.put("status","false");
                jsonObject.put("message",e.getLocalizedMessage());
            } catch (JSONException e1) {
                e1.printStackTrace();
            }
        } catch (Exception e) {
            Log.e(TAG, "Other Error: " + e.getMessage());
            JSONObject jsonObject=new JSONObject();

            try {
                jsonObject.put("status","false");
                jsonObject.put("message",e.getLocalizedMessage());
            } catch (JSONException e1) {
                e1.printStackTrace();
            }
        }
        return null;
    }
    public static JSONObject doGetRequest(HashMap<String, String> param,String url) {
        JSONObject result = null;
        String response;
        Set keys = param.keySet();

        int count = 0;
        for (Iterator i = keys.iterator(); i.hasNext(); ) {
            count++;
            String key = (String) i.next();
            String value = (String) param.get(key);
            if (count == param.size()) {
                Log.e("Key",key+"");
                Log.e("Value",value+"");
                url += key + "=" + URLEncoder.encode(value);

            } else {
                Log.e("Key",key+"");
                Log.e("Value",value+"");

                url += key + "=" + URLEncoder.encode(value) + "&";
            }

        }
/*
        try {
            url=  URLEncoder.encode(url, "utf-8");
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }*/
        Log.e("URL", url);
        OkHttpClient client = new OkHttpClient();

        Request request = new Request.Builder()
                .url(url)
                .build();
        Response responseClient = null;
        try {


            responseClient = client.newCall(request).execute();
            response = responseClient.body().string();
            result = new JSONObject(response);
            Log.e("response", response+"==============");
        } catch (Exception e) {
            JSONObject jsonObject=new JSONObject();

            try {
                jsonObject.put("status","false");
                jsonObject.put("message",e.getLocalizedMessage());
                return  jsonObject;
            } catch (JSONException e1) {
                e1.printStackTrace();
            }
            e.printStackTrace();
        }

        return result;

    }
于 2016-07-22T12:04:05.373 回答