0

为所有这些代码道歉，无论如何我将一个查询重新设计为 Zend 查询的工作方式，这就是我到目前为止所拥有的：

$db = Zend_Registry::get ( "db" );      
    $stmt = $db->query('
    SELECT recipe_pictures.picture_id, recipe_pictures.picture_filename, course.course_name, cuisines.name, recipes.id, recipes.Title, recipes.Method, recipes.author, recipes.SmallDesc, recipes.user_id, recipes.cuisine, recipes.course, recipes.Created_at, recipes.vegetarian, recipes.Acknowledgements, recipes.Time, recipes.Amount, recipes.view_count, recipes.recent_ips, guardian_writers.G_item, guardian_writers.G_type
    FROM recipes
    LEFT JOIN course ON recipes.course = course.course_id
    LEFT JOIN recipe_pictures ON recipes.id = recipe_pictures.recipe_id
    LEFT JOIN cuisines ON recipes.cuisine = cuisines.id
    LEFT JOIN guardian_writers ON recipes.author = guardian_writers.G_author
    WHERE recipes.id = ?', $id);
    $stmt->setFetchMode(Zend_Db::FETCH_ASSOC);
    $recipes = $stmt->fetchAll();

    return $recipes;

上面那个有效，试图正确获得 Zend 版本，我的努力在下面。

    $db = Zend_Registry::get ( "db" );      
    $select = $db->select()
                 ->from(array('r' => 'recipes'))
                 ->join(array('c' => 'course'),
                        'r.course = c.course_id')
                 ->join(array('rp' => 'recipe_pictures'),
                        'r.id = rp.recipe_id')
                 ->join(array('cui' => 'cuisines'),
                        'r.cuisine = cui.id')
                 ->join(array('gw' => 'guardian_writers'),
                        'r.author = gw.G_author')
                 ->where(' id = ? ', $id);

    $recipes = $db->fetchRow($select);

    return $recipes;

如果有人能发现错误，非常感谢，谢谢

4

2 回答 2

2

使用 joinLeft 而不是 join 来生成左连接。

要从表中获取特定列，而不是全部 (*)，请使用以下命令：

->from(array('r' => 'recipes'), array('id', 'title', 'method'))

或者

->joinLeft(array('rp' => 'recipe_pictures'),
                    'r.id = rp.recipe_id',
                    array('picture_id', 'picture_filename')
                    )

要从表中不获取任何列，请将空数组作为第三个参数传递。

于 2010-02-25T23:31:17.927 回答
0

该join方法提供了一个 sql INNER JOIN。如果你想得到一个LEFT JOIN你应该使用joinLeft.

于 2010-02-25T23:34:33.910 回答