我想将文件上传到服务器。所以我使用文件选择器。但是我在某些应用程序中遇到了从 uri 获取真实路径的问题。如果内容是视频、音频或图像,或者我可以直接获取路径,我没有问题。实施的方法是:
public String getRealAudioPathFromURI(Uri contentUri) {
String[] proj = { MediaStore.Audio.Media.DATA };
//This method was deprecated in API level 11
//Cursor cursor = managedQuery(contentUri, proj, null, null, null);
CursorLoader cursorLoader = new CursorLoader(
this,
contentUri, proj, null, null, null);
Cursor cursor = cursorLoader.loadInBackground();
int column_index =
cursor.getColumnIndexOrThrow(MediaStore.Audio.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
它是图像和视频的一部分。但我的问题是当内容采用这种形式时:
content://com.dataviz.dxtg.documentprovider/document/file%3A%2F%2F%2Fmnt%2Fsdcard%2FDownload%2Arbres.png
我试过方法
private String getFilePathFromContentUri(Uri selectedVideoUri,
ContentResolver contentResolver) {
String filePath;
String[] filePathColumn = {MediaStore.MediaColumns.DATA};
Cursor cursor = contentResolver.query(selectedVideoUri, filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
filePath = cursor.getString(columnIndex);
cursor.close();
return filePath;
}
那么如何从 URi 获取真实路径以及是否存在其他内容类型。
下面给出了我的真实路径:
//Uri return from external activity
orgUri = data.getData();
text1.setText("fichier à envoyer " + orgUri.toString() + "\n");
// imagepath = orgUri.toString() ;
//path converted from Uri
//convertedPath = orgUri.getPath();
if(orgUri.toString().contains(IMAGEMEDIA)){
convertedPath = getRealPathFromURI(orgUri);
} else if(orgUri.toString().contains(AUDIOMEDIA)){
convertedPath = getRealAudioPathFromURI(orgUri);
}
else if(orgUri.toString().contains(VIDEOMEDIA)){
convertedPath = getRealvideoPathFromURI(orgUri);
}else {
if(orgUri.toString().contains("content")){
convertedPath = getFilePathFromContentUri(orgUri,
getApplicationContext().getContentResolver());
} else {
convertedPath = orgUri.getPath();
}
}