7

I've been looking around on how to implement a generic trait for commons CRUD and other kinds of operations, I looked at this and this and the method specified are working well.

What I would like to have is a generic method for insertion, my class looks like this at the moment (non generic implementation):

object CampaignModel {
  val campaigns = TableQuery[Campaign]

  def insert(campaign: CampaignRow)(implicit s: Session) = {
    campaigns.insert(campaign)
  }
}

What I tried so far, following the first link, was this (generic implementation):

trait PostgresGeneric[T <: Table[A], A]  {
  val tableReference = TableQuery[T]

  def insertGeneric(row: ? What type goes here ?)(implicit s: Session) = tableReference.insert(row)

}

When I inspect the insert method it looks like the right type should be T#TableElementType but my knowledge is pretty basic and I can't wrap my head around types, I tried T and A and the compiler says that the classtype does not conform to the trait one's.

Other infos, the tables are generated with the slick table generation tools

case class CampaignRow(id: Long, name: Option[String])

/** Table description of table campaign. Objects of this class serve as prototypes for rows in queries. */
class Campaign(tag: Tag) extends Table[CampaignRow](tag, "campaign") {
  def * = (id, name) <>(CampaignRow.tupled, CampaignRow.unapply)

  /** Maps whole row to an option. Useful for outer joins. */
  def ? = (id.?, name).shaped.<>({
    r => import r._; _1.map(_ => CampaignRow.tupled((_1.get, _2)))
  }, (_: Any) => throw new Exception("Inserting into ? projection not supported."))

  /** Database column id AutoInc, PrimaryKey */
  val id: Column[Long] = column[Long]("id", O.AutoInc, O.PrimaryKey)
  /** Database column name  */
  val name: Column[Option[String]] = column[Option[String]]("name")
}
4

1 回答 1

11

我设法使它起作用,这是我的一般特征:

import scala.slick.driver.PostgresDriver
import scala.slick.driver.PostgresDriver.simple._
import path.to.RichTable

trait PostgresGeneric[T <: RichTable[A], A] {

  val tableReference: TableQuery[T]

  def insert(row: T#TableElementType)(implicit s: Session) = 
    tableReference.insert(row)

  def insertAndGetId(row: T#TableElementType)(implicit s: Session) = 
    (tableReference returning tableReference.map(_.id)) += row

  def deleteById(id: Long)(implicit s: Session): Boolean = 
    tableReference.filter(_.id === id).delete == 1

  def updateById(id: Long, row: T#TableElementType)(implicit s: Session): Boolean = 
    tableReference.filter(_.id === id).update(row) == 1

  def selectById(id: Long)(implicit s: Session): Option[T#TableElementType] = 
    tableReference.filter(_.id === id).firstOption

  def existsById(id: Long)(implicit s: Session): Boolean = {
    (for {
      row <- tableReference
      if row.id === id
    } yield row).firstOption.isDefined
  }
}

具有 id 字段的抽象类在哪里RichTable,具有上限约束的 this 可用于获取 id 字段(有关更多信息,T#TableElementType请参阅此):

import scala.slick.driver.PostgresDriver.simple._
import scala.slick.jdbc.{GetResult => GR}

abstract class RichTable[T](tag: Tag, name: String) extends Table[T](tag, name) {
  val id: Column[Long] = column[Long]("id", O.PrimaryKey, O.AutoInc)
}

我的竞选表现在看起来像这样:

import scala.slick.driver.PostgresDriver.simple._
import scala.slick.jdbc.{GetResult => GR}
import scala.slick.lifted.TableQuery

case class CampaignRow(id: Long, name: Option[String])

class Campaign(tag: Tag) extends RichTable[CampaignRow](tag, "campaign") {
  def * = (id, name) <>(CampaignRow.tupled, CampaignRow.unapply)

  def ? = (id.?, name).shaped.<>({
    r => import r._; _1.map(_ => CampaignRow.tupled((_1.get, _2)))
  }, (_: Any) => throw new Exception("Inserting into ? projection not supported."))

  override val id: Column[Long] = column[Long]("id", O.AutoInc, O.PrimaryKey)
  val name: Column[Option[String]] = column[Option[String]]("name")
}

实现泛型特征的模型如下所示:

 object CampaignModel extends PostgresGeneric[Campaign, CampaignRow] {

   override val tableReference: PostgresDriver.simple.TableQuery[Tables.Campaign] = 
     TableQuery[Campaign]

   def insertCampaign(row: CampaignRow) = {
     insert(CampaignRow(0, "test"))
   }
 }
于 2014-04-30T18:13:06.270 回答