1

我希望用户在集合 [1, 100] 中输入 10 个唯一整数。到目前为止，这是我的代码：

user_list = []
print "\nChoose any 10 discrete integers in the set [1, 100]. Do not choose duplicates."

i = 1

while i < 11:
    try:
        number_choice = int(raw_input("\nNumber %d?\n> " % i))

        if (0 <= number_choice <= 100) and isinstance(number_choice, int):
            i += 1
            user_list.append(number_choice)
            print "Your list so far: %r" % user_list
        elif (number_choice < 0) or (number_choice > 100):
            print "'I said to keep it in the set [1, 100].'"
            pass
        else:
            pass

    except ValueError:
        print "'That isn't a discrete integer, is it?'"

print sorted(user_list)

为了防止重复，我想将第一个更改为if：

if (0 <= number_choice <= 100) and (isinstance(number_choice, int)) and (number_choice not in user_list):

"Number %d?" % i这将起作用，除非如果用户输入重复项，它只会再次重复提示。如何修改此代码，使其首先显示提示'I said no duplicates.'，然后恢复循环？

4

2 回答 2

4

行前i += 1：

if number_choice in user_list:
    print 'No duplicates!'
    continue
于 2014-04-27T02:02:35.823 回答
0

首先在 if 语句中检查重复，然后检查有效整数并将其添加到“if else”中的列表中。

于 2014-04-27T02:02:51.910 回答