0 
def list_ajax(reqest):
    #q = request.GET.get('q',None)
    #get all where var = q.
    return ...
list_ajax = condition(etag_func=list_ajax)(list_ajax)

如您所见，如果结果相同，我正在尝试向客户端返回 304。但是，我收到了这个 Django 错误，为什么？：

Traceback:
File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py" in get_response
  92.                 response = callback(request, *callback_args, **callback_kwargs)
File "/usr/local/lib/python2.6/dist-packages/django/views/decorators/http.py" in inner
  130.                 response['ETag'] = quote_etag(res_etag)
File "/usr/local/lib/python2.6/dist-packages/django/utils/http.py" in quote_etag
  118.     return '"%s"' % etag.replace('\\', '\\\\').replace('"', '\\"')

Exception Type: AttributeError at /list/ajax/
Exception Value: 'HttpResponse' object has no attribute 'replace'

编辑：我这样做了：

def etag_generate(p):
    thestring =  cPickle.dumps(p)
    return thestring

@etag(etag_generate)
def list_ajax(request):
    ...
    etag_generate(mydictresults)
    return render_to_response("list.html",mydictresults)

我把所有的结果都变成了一个字符串，希望可以从这个字典中生成一个散列。但是，@etag 似乎不允许我生成 cPickle。错误是：

Exception Type: TypeError at /list/ajax/ 
Exception Value: can't pickle file objects
4

2 回答 2

0

正确的etag_func会返回一些可序列化的数据。在你的情况下，最好的选择是这样的：

@etag(_get_list)
def list_ajax(request):
    objects = _get_list(request)
    return render_to_response("list.html", {"objects": objects})

def _get_list(request):
    q = request.GET["q"]
    # find and return records here
    # ...
于 2010-02-25T01:06:29.503 回答
0

固定的。

将请求传入。

def list_ajax_etag(request):
    return str(request.GET.get('l',''))+str(request.GET.get('a',''))
于 2010-02-25T08:12:32.763 回答