我在一个项目中使用了 Flask-Restful,我还使用工厂模式来创建Flask
对象。现在的问题是,当我尝试访问时,Flask 给了我 404 错误,http://localhost:5000/api/v1/user/
但是当我(通过调试器)探索 Flask 应用程序对象url_map
时,我的 API 规则就在那里。所以,如果有人遇到同样的问题,我会采取任何可能的解决方案。
我有以下创建 API 应用程序的函数:
def create_app(settings_override=None):
"""
Returns the API :class:`Flask` instance.
:param settings_override: dictionary of settings to override.
"""
app = factory.create_app(__name__, __path__, settings_override)
api = Api(app, prefix='/api/v1', catch_all_404s=True)
# API endpoints connected to the User model.
api.add_resource(UserAPI, '/user/', endpoint='user')
return app
UserAPI 类的代码(Flask-Restful 使用):
class UserAPI(Resource):
"""
API :class:`Resource` for returning the details of a user.
This endpoint can be used to verify a user login credentials.
"""
def get(self):
return {'hello': 'world'}, 200
def post(self):
pass
factory.create_app
功能:
def create_app(package_name, package_path, settings_override=None):
"""
Returns an instance of Flask configured with common functionnalities for
Cubbyhole.
:param package_name: application package name
:param package_path: application package path
:param settings_override: a dictionnary of settings to override
"""
app = Flask(package_name, instance_relative_config=True)
app.config.from_object('cubbyhole.settings')
app.config.from_pyfile('settings.cfg', silent=True)
if settings_override is not None:
app.config.update(settings_override)
db.init_app(app)
register_blueprints(app, package_name, package_path)
return app
Python 版本 2.7 Flask v. Flask-Restful 版本