php - 在 Symfony 2.4 Doctrine 中获取 Max of AVG

Question

我需要在 symfony 学说中获得 AVG 列表的 MAX

我获得平均值的学说查询如下：

SELECT p,AVG(p.pathTime) as avgtime 
FROM ShopperAnalyticsEntityBundle:Path p 
 JOIN p.shopper sh JOIN p.floor f 
 JOIN f.store s 
WHERE p.floor=".$floorId." ".$filter." 
GROUP BY p.xPath, p.yPath

为了获得平均值列表的最大值，我将其修改为（在引用this之后）：

SELECT MAX(avgtime) as maxtime 
FROM (SELECT p,AVG(p.pathTime) as avgtime 
      FROM ShopperAnalyticsEntityBundle:Path p 
       JOIN p.shopper sh 
       JOIN p.floor f 
       JOIN f.store s 
      WHERE p.floor=".$floorId." ".$filter." 
      GROUP BY p.xPath, p.yPath)

我收到以下错误：

[Semantical Error] line 0, col 38 near '(SELECT p,AVG(p.pathTime)': Error: Class '(' is not defined

所以我切换到本机 SQL 以获得相同的结果：

$maxSQL   = "SELECT MAX(t.avgtime) as maxtime FROM ( SELECT AVG(p.path_time) as avgtime FROM  path p JOIN shopper sh JOIN floor f JOIN store s WHERE p.floor_id=".$floorId." ".$filter." GROUP BY p.x_path, p.y_path ) t ";

$connection = $em->getConnection();
$statement = $connection->prepare($maxSQL);
$statement->execute();
$results = $statement->fetchAll();

我得到了结果，但 SQL 需要 23.4457 秒才能运行

谁能在 Doctrine 中提出一个简单的方法来解决这个问题。

Answer 1

你应该这样使用 dotrine ：

$query = Doctrine_Query::create()
  ->select('MAX(avgtime) as maxtime ')
  ->from('(SELECT p,AVG(p.pathTime) as avgtime 
           FROM ShopperAnalyticsEntityBundle:Path p 
           JOIN p.shopper sh 
           JOIN p.floor f 
           JOIN f.store s 
           WHERE p.floor=".$floorId." ".$filter." 
           GROUP BY p.xPath, p.yPath)
        ')
  ->execute();

你怎么你的？