如何NSDate
在 iOS 上将字符串转换为字符串?
问问题
76773 次
6 回答
197
NSString *dateStr = @"20100223";
// Convert string to date object
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyyMMdd"];
NSDate *date = [dateFormat dateFromString:dateStr];
// Convert date object to desired output format
[dateFormat setDateFormat:@"EEEE MMMM d, YYYY"];
dateStr = [dateFormat stringFromDate:date];
[dateFormat release];
希望这会帮助你。
于 2010-02-23T03:53:17.210 回答
9
你会想看看NSDateFormatter。确定日期字符串的格式,然后用于dateFromString:
将字符串转换为 NSDate 对象。
于 2010-02-22T14:27:55.483 回答
5
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"dd/MM/YYYY"];
NSDate *date = [dateFormat dateFromString:dateStr];
list = [self getYear:date];
- (NSMutableArray *)getYear:(NSDate*)date
{
NSDateComponents *components = [[NSCalendar currentCalendar] components:NSCalendarUnitDay | NSCalendarUnitMonth | NSCalendarUnitYear fromDate:date];
int year = [components year];
int month = [components month];
int day = [components day];
NSLog(@"%d",year);
NSMutableDictionary *dateDict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:[NSString stringWithFormat:@"%d", day], @"day", [NSString stringWithFormat:@"%d", month], @"month", [NSString stringWithFormat:@"%d", year], @"year", nil];
return dateDict;
}
于 2015-03-13T07:08:19.777 回答
3
我在 Swift 中的工作版本
func dateFor(timeStamp: String) -> NSDate
{
let formater = NSDateFormatter()
formater.dateFormat = "HH:mm:ss:SSS - MMM dd, yyyy"
return formater.dateFromString(timeStamp)!
}
func timeStampFor(date: NSDate) -> String
{
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "HH:mm:ss:SSS - MMM dd, yyyy"
return dateFormatter.stringFromDate(date)
}
于 2016-04-22T20:05:24.667 回答
2
即使您有 sqlite DB,也是一种简单的方法:
// NSTimeInterval is basically typedef of double so you can receive it as double also.
NSTimeInterval *current = [[NSDate date] timeIntervalSince1970];
[DB addToDB:current];
//retrieve the date from DB
NSDate *retrievedDateItem = [[NSDate alloc] initWithTimeIntervalSince1970:[getDBValueAsDouble]]; //convert it from double (NSTimeInterval) to NSDate
// Set the style
[dateFormatter setDateStyle:NSDateFormatterMediumStyle];
[dateFormatter setTimeStyle:NSDateFormatterMediumStyle];
// Converted to string
NSString *convertedDate = [dateFormatter stringFromDate:retrievedDateItem];
此示例的输出:
2015 年 8 月 3 日,下午 12:27:50
于 2015-08-03T09:37:23.510 回答
1
+(NSDate*)str2date:(NSString*)dateStr{
if ([dateStr isKindOfClass:[NSDate class]]) {
return (NSDate*)dateStr;
}
NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd"];
NSDate *date = [dateFormat dateFromString:dateStr];
return date;
}
于 2015-06-12T08:34:35.927 回答