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我正在处理一个类似于这里的数据框：

ID = c("1","1","1","1","1","1","1","2","2","2","2","2","2","2","2","2","2","2","2","2","2") 
TIME = c("0", "0.5", "1","1.5","2","2.5","3","0","0", "0.5","0.5", "1","1","1.5","1.5","2","2","2.5","2.5","3","3") 
OBS = c("0", "0.73", "0.98", "1.24", "2.06","2.56","4.01", "0", "0.03", "0.76", "0.85", "2.13","2.78","3.9", "4.1", "5.4", "5.6", "7.8", "8.0","8.4","8.8") 
VISITNUM = c("1","1","1","1","1","1","1","1","2", "1","2","1","2","1","2","1","2","1","2","1","2") 
DF = data.frame(ID, TIME, OBS, VISITNUM)

我在订购数据框时遇到问题 - 基本上我想按以下时间顺序订购我的数据：

TIMEORDERED <- c("0","0.5","1","1.5","2","2","2.5","3")

给这个

ID = c("1","1","1","1","1","1","1","2","2","2","2","2","2","2","2","2","2","2","2","2","2") 
TIME = c("0", "0.5", "1","1.5","2","2.5","3","0", "0.5", "1","1.5","2","2.5","3","0", "0.5", "1","1.5","2","2.5","3") 
OBS= c("0", "0.73", "0.98", "1.24", "2.06","2.56","4.01", "0", "0.76", "2.13","3.9", "5.4", "7.8", "8.4", "0.03", "0.85", "2.78", "4.1","5.6","8.0","8.8") 
VISITNUM = c("1","1","1","1","1","1","1","1","1","1","1","1","1","1","2","2","2","2","2","2","2")
DFIWANT = data.frame(ID, TIME, OBS, VISITNUM)

问题是同一主题的测量值 (DF$ID = 2)（但访问次数不同，请参阅 DF$VISITNUM）。

我怀疑 plyr 包中的 order() 函数或arrange() 函数是我的朋友，但我的尝试没有结果。

任何帮助，将不胜感激。

真诚的

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1 回答 1

0

是的，您可以使用 来执行此操作order()，您只需要指定您希望数据框按以下顺序排序的变量：

DF.ordered <- DF[order(DF$ID, DF$VISITNUM, DF$TIME),]

您也可以arrange()从 plyr 使用：

library(plyr)
DF.arranged <- arrange(DF, ID, VISITNUM, TIME)
于 2014-04-16T11:47:40.153 回答