4

我试图通过在 setTimeout 函数中编辑范围来触发 ng-show。setTimeout 是数据库查询回调的占位符。

索引.html:

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.15/angular.min.js"></script>

<script src="script.js"></script>

<div ng-controller="c1">

    <div ng-show="{{show}}"  >

        test it

    </div>

</div>

脚本.js:

var amTestNgShow = angular.module('amTestNgShow',[]);

amTestNgShow.controller('c1', ['$scope', function($scope) {

    // this works: $scope.show = true;

    setTimeout(function(){

        $scope.show = true; // works not

        // does not help: $scope.$apply();

    }, 1000)

}]);

这在 setTimeout 内如何实现?谢谢!

http://plnkr.co/edit/RPS2vZAlVfhliQKteSSK

更新:如上所述, setTimeout 不是问题,它仅用于生成可重现的 stackoverflow 问题。在我的项目中,我构建了一个服务:

amProject1.service('asBasic', ['$http', '$q', function($http, $q){

    var asBasic = {};

    asBasic.docName = '';

    var doc = {};

    asBasic.get = function(id){

        var deferred = $q.defer();

        $http({method:'GET', url: '/' + this.docName + '/' + id})
            .success(function(data, status, headers, config){

                if(data === undefined){

                    deferred.reject("The requested " + asBasic.docName + " was not found.")

                }

                doc = data;
                deferred.resolve(doc);

            })
            .error(function(data, status, headers, config){

                deferred.reject(status);

            })

       return deferred.promise;

    }


    return asBasic;

}]);

像使用它一样

amProject1.controller('acDoc1', ['$scope', '$routeParams', 'asBasic', function($scope, $routeParams, asBasic){

    asBasic.docName = 'doc1';

    // this works: $scope.show = true;

    asBasic.get($routeParams._id)
        .then(function(data){

            $scope.doc1 = data;

            $scope.show = true; // works not

            // does not help: $scope.$apply();

            // ...

        }
        // ...
4

4 回答 4

2

我注意到您在模板中绑定到 {{show}}。大括号应该被删除,因为它们在 AngularJS 属性中。

于 2014-04-16T09:39:23.977 回答
2

这是因为 setTimeout 在$scope进程之外。注入并$timeout改用。

http://docs.angularjs.org/api/ng/service/$timeout

例如:

amTestNgShow.controller('c1', ['$scope', '$timeout', function($scope, $timeout) {
    $timeout(function(){
        $scope.show = true;
    }, 1000);
}]);

如果您确实想改用$scope.apply,我认为您只是使用错误。您在范围编辑后不调用$scope.apply(),而是将它们放在 apply 函数中:

$scope.apply(function(){
    $scope.show = true;
});
于 2014-04-16T09:12:10.383 回答
1

我的帖子的后期评论:mrida 是对的(谢谢),必须删除大括号......

<div ng-controller="c1">

    <div ng-show="show">

        test it

    </div>

</div>

也可以用 ng-style 来解决。

html:

...

<div ng-controller="c1">

    <div ng-style="{'visibility': show}">

        test it

    </div>

</div>

...

控制器:

...

setTimeout(function(){

    $scope.show = "visible"; // or $scope.show = "hidden"

    $scope.$apply();

}, 1000)

...
于 2014-04-17T07:49:35.723 回答
-1

使用$timeout代替setTimeout'show'代替'{{show}}'

<div ng-show="show">
    test it
</div>
于 2014-04-16T09:39:21.937 回答