3

我想开发一个通过 authorize.net 进行支付处理的应用程序

但每次我得到未知的错误。

首先，我填充所有文本框并在按钮单击事件中使用这些值。
我的代码是：

txtAmount=Double.parseDouble(Amount.getText().toString());
txtFName = FName.getText().toString();
txtLName=LName.getText().toString();
txtAddress=Address.getText().toString();
txtCity=City.getText().toString();
txtState=State.getText().toString();
txtzipcode=zipcode.getText().toString();
txtEmail=Email.getText().toString();
txtCreditCard=CreditCard.getText().toString();
txtCVV2=CVV2.getText().toString(); 

drpMonth=selectedmonth;
drpYear=selectedyear;
date= drpMonth.concat(drpYear);

try {
    URL post_url = new URL("https://test.authorize.net/gateway/transact.dll");

    Hashtable post_values = new Hashtable();

    // the API Login ID and Transaction Key must be replaced with valid values
    post_values.put ("x_login", "8SX5gkJb46g");
    post_values.put ("x_tran_key", "8Wx295Gr4hd9Y5kd");

    post_values.put ("x_version", "3.1");
    post_values.put ("x_delim_data", "TRUE");
    post_values.put ("x_delim_char", "|");
    post_values.put ("x_relay_response", "FALSE");

    post_values.put ("x_type", "AUTH_CAPTURE");
    post_values.put ("x_method", "CC");
    post_values.put ("x_card_num", txtCreditCard);
    post_values.put ("x_exp_date", date);

    post_values.put ("x_amount", txtAmount);
    post_values.put ("x_description", "Sample Transaction");

    post_values.put ("x_first_name",txtFName);
    post_values.put ("x_last_name",txtLName);
    post_values.put ("x_address", txtAddress);
    post_values.put ("x_city", txtCity);
    post_values.put ("x_state",txtState);
    post_values.put ("x_zip", txtzipcode);
    post_values.put ("x_email", txtEmail);
    // Additional fields can be added here as outlined in the AIM integration
    // guide at: http://developer.authorize.net

    // This section takes the input fields and converts them to the proper format
    // for an http post.  For example: "x_login=username&x_tran_key=a1B2c3D4"

    StringBuffer post_string = new StringBuffer();
    Enumeration keys = post_values.keys();
    while( keys.hasMoreElements() ) {
        String key = URLEncoder.encode(keys.nextElement().toString(),"UTF-8");
        String value = URLEncoder.encode(post_values.get(key).toString(),"UTF-8");
        post_string.append(key + "=" + value + "&");
    }

    // Open a URLConnection to the specified post url
    URLConnection connection = post_url.openConnection();
    connection.setDoOutput(true);
    connection.setUseCaches(false);

    // this line is not necessarily required but fixes a bug with some servers
    connection.setRequestProperty("Content-Type","application/x-www-form-urlencoded");

    // submit the post_string and close the connection


    DataOutputStream requestObject = new DataOutputStream(connection.getOutputStream());
    requestObject.write(post_string.toString().getBytes());
    requestObject.flush();
    requestObject.close();

    // process and read the gateway response
    BufferedReader rawResponse = new BufferedReader(new InputStreamReader(connection.getInputStream()));
    String line;
    String responseData = rawResponse.readLine();
    rawResponse.close();                         // no more data

    // split the response into an array
    String [] responses = responseData.split("|");

    // The results are output to the screen in the form of an html numbered list.

    for(Iterator iter=Arrays.asList(responses).iterator(); iter.hasNext();) {
        result="\n"+ iter.next() +"&nbsp";
        tv.setText(result);
        //out.println("<LI>" + iter.next() + "&nbsp;</LI>");
    }

    setContentView(tv);
} catch(Exception e) {
    tv.setText(e.getMessage());
    setContentView(tv);
}

谁能帮我？

通过 setContentView 我正在显示我的拆分结果，我只得到未知的错误异常。没有显示其他描述。我的方法是错误的还是有其他方法可以实现付款处理？

4

3 回答 3

1

感谢您的代码 :) 我从您的代码中获得了新的想法，以在 android 中实现 authorize.net 我不知道您遇到了什么错误，但是当我尝试使用 post url 进行集成时，我遇到了一个错误，我在其中添加了“x_market_type”我的代码，我得到了结果 

 post_values.put ("x_market_type", "2");
我还集成了 authorize.net 提供的示例代码，但是对于我的自定义要求，您的代码对我有很大帮助。

如果您需要任何帮助而不是发表评论。:)

于 2013-10-04T10:15:07.517 回答
0

建议您改用 HTTPClient，如本示例所示 如何在 Android 上使用 cookie 发出 http 请求？

从我在您的代码中可以看到：

  1. 本节将在最后给出一个额外的 & 
    while( keys.hasMoreElements() ) {
String key = URLEncoder.encode(keys.nextElement().toString(),"UTF-8");
String value = URLEncoder.encode(post_values.get(key).toString(),"UTF-8");
post_string.append(key + "=" + value + "&");

    }

  2. 您只读取了服务器返回的内容的一行。即使内容可能放在一行中，HTTP 标头也会跨越几行
String responseData = rawResponse.readLine();
  1. 您使用服务器可能不接受的默认用户代理请求标头

如果你想尝试修复你当前的代码，我建议你调试它或抛出一些日志语句（你可以使用例如 aLogCat 应用程序查看）

于 2010-02-22T22:43:45.563 回答
0

//Authorize.net android 实现使用 volley post。这可能会对您和 rashmi 有所帮助，感谢您的代码和 bhavin 的错误帮助

final String txtAmount=totalprice.getText().toString();
        final String txtFName = first_name;
        final String txtLName=last_name;
        final String txtAddress=address_1;
        final String txtCity=city;
        final String txtState=state;
        final String txtzipcode=postcode;
        final String txtEmail=email;
        final String txtCreditCard=CardNumber;
        String txtCVV2=Cvv;

        String drpMonth=Month;
        String drpYear=Year;
        final String date= drpMonth.concat(drpYear);



        String url = Uri.parse("https://test.authorize.net/gateway/transact.dll").buildUpon()
                .build().toString();

        StringRequest stringRequest = new StringRequest(Request.Method.POST, url,
                new Response.Listener<String>() {
                    @Override
                    public void onResponse(String response) {
                        Log.e("====", response);
                        if (dialog != null && dialog.isShowing()) {
                            dialog.dismiss();
                        }

                        try {
                            JSONObject jsonObject = new JSONObject(response);



                        } catch (JSONException e) {
                            e.printStackTrace();
                        }
                    }
                },
                new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {
                        Log.e("====", error.toString());
                        if (dialog != null && dialog.isShowing()) {
                            dialog.dismiss();
                        }
                    }
                }) {

            @Override
            protected Map<String, String> getParams() throws AuthFailureError {
                Map<String, String> post_values = new HashMap<String, String>();
                post_values.put ("x_login", "8RtP63yV");
                post_values.put ("x_tran_key", "9A4a59AThQh4c6wG");

                post_values.put ("x_version", "3.1");
                post_values.put ("x_delim_data", "TRUE");
                post_values.put ("x_delim_char", "|");
                post_values.put ("x_relay_response", "FALSE");
                post_values.put ("x_market_type", "2");

                post_values.put ("x_type", "AUTH_CAPTURE");
                post_values.put ("x_method", "CC");
                post_values.put ("x_card_num", txtCreditCard);
                post_values.put ("x_exp_date", date);

                post_values.put ("x_amount", txtAmount);
                post_values.put ("x_description", "Sample Transaction");

                post_values.put ("x_first_name",txtFName);
                post_values.put ("x_last_name",txtLName);
                post_values.put ("x_address", txtAddress);
                post_values.put ("x_city", txtCity);
                post_values.put ("x_state",txtState);
                post_values.put ("x_zip", txtzipcode);
                post_values.put ("x_email", txtEmail);
                return post_values;
            }
        };

        RequestQueue requestQueue = Volley.newRequestQueue(this);
        requestQueue.add(stringRequest);
于 2017-07-03T09:10:14.997 回答