1
select * 
from 
( 
     select year, 
            week,  
            salesperson,
            count(*) as transactions,  
            rank() over(partition by week order by count(*) desc) as ranking 
     from sales
     where year = '2010',               
     group by year,  
              week, 
              salesperson  

) temp 
where ranking <= 10

该查询返回一年中每周前 10 名销售人员的列表(以交易次数计)。

如何在我的结果中添加列:

  1. 该销售人员上周的排名
  2. 今年前 10 名的总周数
  3. 连续进入前 10 周(从第 1 周开始)
  4. 连续几周进入前 10 名(如果可能,从上一年开始)

您能否就如何解决此类问题提供一般性建议?

PS:使用SQL Server 2008

4

2 回答 2

1

实际上,我不相信 View 是最好的方法。您可以在 CTE 中执行这种逻辑,并将整个事情组合成一个查询。例如,除了连续逻辑之外,这是我所拥有的一切:

;With 
    SalesDateParts As
    (
        Select DatePart(wk, SaleDate) As WeekNum, DatePart(yy, SaleDate) As [Year], SalesPersonId
        From #Sales
    )
    , SalesByWeek As
    (
        Select [Year], WeekNum, SalesPersonId, Count(*) As SaleCount
            , RANK() OVER( PARTITION BY [Year], [WeekNum] ORDER BY Count(*) DESC ) As SaleRank
        From SalesDateParts
        Group By [Year], WeekNum, SalesPersonId
    )
    , PrevWeekTopSales As
    (
        Select [Year], [WeekNum], SalesPersonId, SaleCount
        From SalesByWeek
        Where [Year] = DatePart(yyyy, DateAdd(d, -7, CURRENT_TIMESTAMP))
            And WeekNum = DatePart(wk, DateAdd(d, -7, CURRENT_TIMESTAMP))
    )
    , WeeksInTop10 As
    (
        Select SalesPersonId, Count(*) As Top10Count
        From SalesByWeek
        Where SaleRank <= 10
        Group By SalesPersonId
    )
Select *
From Salespersons
    Left Join WeeksInTop10
        On WeeksInTop10.SalesPersonId = SalesPersons.SalesPersonId
    Left Join PrevWeekTopSales
        On PrevWeekTopSales.SalesPersonId = SalesPersons.SalesPersonId

“连续”的逻辑可能需要一个日历表,其中包含每天的值以及给定日期的年和周的列。

于 2010-02-21T07:44:17.853 回答
0

我的建议是在视图中分别进行其他查询,然后由销售人员加入(我认为这是关键)

逻辑是这个查询很好,很干净,很容易理解。否则 - 我认为解决这个问题的方法是开始编写 TSQL 函数来计算其他值,但我认为这些函数无论如何都会有查询。

于 2010-02-21T06:15:08.983 回答