我有一个遍历用户 _id 字符串的模板。
<div class="page-header"><h4>Colleagues</h4></div>
<ul class="list-group">
{{#each colleague}}
<li class="list-group-item">
<div class="colleague">
{{nameOrEmail}}
</div>
</li>
{{/each}}
</ul>
当我打电话
nameOrEmail: function () {
if (myTeam.ready()) {
console.log ("into function nameorEmail");
console.log(this);
var self=this;
if (self) {
var colleague=Meteor.users.findOne({_id:self});
console.log(colleague);
if (colleague.username)
return colleague.username;
else if (colleague.emails.count()>0)
return collegue.emails[0].address;
}}
return null;
在模板中,它在执行 var colleague=Meteor.users.findOne({_id:self}) 时抛出错误。具体来说,它会抛出一个类型错误,即对象 0 没有方法“substr”
manageAccount.js?a86dcce62b84091cf50c653de6d2db7f0102a155:59
Exception from Deps recompute function: TypeError: Object 0 has no method 'substr'
at http://localhost:3000/packages /minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1211:33
at Function._.each._.forEach (http://localhost:3000/packages/underscore.js?0a80a8623e1b40b5df5a05582f288ddd586eaa18:159:22)
at isOperatorObject (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1210:5)
at compileValueSelector (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1406:14)
at http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1386:9
at Function._.each._.forEach (http://localhost:3000/packages/underscore.js?0a80a8623e1b40b5df5a05582f288ddd586eaa18:164:22)
at compileDocumentSelector (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1369:5)
at _.extend._compileSelector (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1346:12)
at new Minimongo.Matcher (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:1289:27)
at new LocalCollection.Cursor (http://localhost:3000/packages/minimongo.js?4ee0ab879b747ffce53b84d2eb80d456d2dcca6d:142:20)
我已经确认我可以从 Javascript 控制台运行 findOne 命令并获得预期的结果。我还通过流星函数跟踪了程序的执行。在我看来,selector.js 文件中的函数 _.type 可能是罪魁祸首。
LocalCollection._f = {
// XXX for _all and _in, consider building 'inquery' at compile time..
_type: function (v) {
if (typeof v === "number")
return 1;
if (typeof v === "string")
return 2;
if (typeof v === "boolean")
return 8;
if (isArray(v))
return 4;
if (v === null)
return 10;
if (v instanceof RegExp)
// note that typeof(/x/) === "object"
return 11;
if (typeof v === "function")
return 13;
if (v instanceof Date)
return 9;
if (EJSON.isBinary(v))
return 5;
if (v instanceof LocalCollection._ObjectID)
return 7;
return 3; // object
当我用 v 作为字符串跟踪它时(在 Javascript 调试器局部变量监视器中确认):
String {0: "d", 1: "e", 2: "P", 3: "k", 4: "j", 5: "N", 6: "j", 7: "4", 8: "8", 9: "T", 10: "e", 11: "F", 12: "v", 13: "d", 14: "z", 15: "v", 16: "K", length: 17}
它返回值 3(对象)而不是 2(字符串)。
我怀疑这是我问题的根本原因。这是流星中的错误吗?有谁知道如何解决这个问题?
提前感谢您的帮助。