当我试图用 safari 测试它时，即它没有显示任何结果:( 而是加载一个空页面。，我的联系表也一样。，
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
</head>
<body>
<div id="content"><br/>
Fill out your criteria for searching and see the result below<br/><br/>
<?php
include('connection.php');
$result = mysql_query("SELECT * FROM mytable") or die (mysql_error());
if(isset($_POST['btnSearch']))
{
$query = $_POST['budget'];
$query1 = $_POST['location'];
//$query2 = $_POST['bedroom'];
$query3 = $_POST['building'];
{
if (isset($_POST['1br'])&&
$_POST['1br']=='1BR'){
$query2=$_POST['1br'];
}
}
{
if (isset($_POST['2br'])&&
$_POST['2br']=='2BR'){
$query2=$_POST['2br'];
}
}
{
if (isset($_POST['3br'])&&
$_POST['3br']=='3BR'){
$query2=$_POST['3br'];
}
}
$min_length = 0;
if(strlen($query) >= $min_length)
{
$query = htmlspecialchars($query); mysql_real_escape_string($query);
$row_result = mysql_query("SELECT * FROM table WHERE(`location` like'%".$query1."%') && (`sale_price` like '%".$query."%') && (`numberoftb` like '%".$query2."%') && (`building_name` like '%".$query3."%')");
if(mysql_num_rows($row_result) > 0)
{
while($result = mysql_fetch_array($row_result))
{
echo'<span class="sub_header">TRANSACTION NUMBER:</span> '.$result['transaction_number'];
echo'<span class="sub_header"><br/>LOCATION:</span> '.$result['location'];
echo'<span class="sub_header"><br/>FOR LEASE:</span> '.$result['for_lease'];
echo'<span class="sub_header"><br/>FOR SALE:</span> '.$result['for_sale'];
echo'<span class="sub_header"><br/>BUILDING NAME:</span> '.$result['building_name'];
echo'<span class="sub_header"><br/>DEVELOPER:</span> '.$result['developer'];
echo'<span class="sub_header"><br/>NUMBER OF BEDROOM:</span> '.$result['numberoftb'];
echo'<span class="sub_header"><br/>NUMBER OF ROOM:</span> '.$result['numberofroom'];
echo'<span class="sub_header"><br/>FULLY FURNISHED:</span> '.$result['fullyfurnished'];
echo'<span class="sub_header"><br/>WITH BALCONY:</span> '.$result['withbalcony'];
echo'<span class="sub_header"><br/>SALE PRICE:</span> '.$result['sale_price'];
echo'<span class="sub_header"><br/>LEASE PRICE:</span> '.$result['lease_price'];
echo'<span class="sub_header"><br/>DESCRIPTION:</span> '.$result['description'];
echo'<span class="sub_header"><br/>FLOOR AREA:</span> '.$result['floor_area'];
echo'<span class="sub_header"><br/>MORE DETAILS:</span><a href="view.php?transaction_number='.$result['transaction_number'].'">View</a></td>';
echo'<br/><br/>';
}}
else{
echo'<span class="header">No Result</span>';
} }
else{
echo "Minimum length is ".$min_length;
}
}
?>
</div>
<div id="sidebar">
<section class="widget">
<center><h4 class="widgettitle"><br/>Search!</h4><br/>
<form name="searchcondo" method="post" action="" >
<span class="sub_header">Enter the BUDGET you want:</span><br /><input type="text" name="budget" maxlength="50" size="30"><br/>
<span class="sub_header">Building Name:</span><br /><input type="text" name="building" maxlength="80" size="30"><br/>
<span class="sub_header">Number of BEDROOMS:</span><br /><input type="checkbox" name="1br" value="1BR">1BR<input type="checkbox" name="2br" value="2BR">2BR<input type="checkbox" name="3br" value="3BR">3BR<br/>
<span class="sub_header">Location:</span><br /><input type="text" name="location" maxlength="80" size="30"><br/>
<br /><input type="submit" name="btnSearch" value="Search">
</form>
</center>
</section>
</body>
</html>
我已经上传了它，上面的代码适用于 FireFox 和 Google Chrome。Safari 和 IE 的可能解决方案是什么？我是新手请帮助我.. 谢谢.. :(